Chemistry: Post your doubts here!

[The Sarcastic Retard]

they r blocked in my country

Hows preps?

 

[Lola_sweet]

Hows preps?

we will talk on ur wall i ve a bad habit of ruining threads

I want to see 'em. XPFMember upload PDFs here, please?

I do too :/

 

[The Sarcastic Retard]

we will talk on ur wall i ve a bad habit of ruining threads

I do too :/

Okieks..

 

[DESTROYER1198]

can someone please help. I would really appreciate it if someone can explain for me s12 qp23 Q5)C)

 

[The Sarcastic Retard]

can someone please help. I would really appreciate it if someone can explain for me s12 qp23 Q5)C)

Sorry, m not into organic yet. I have to make it stronger. Lemme try though.

 

[The Sarcastic Retard]

can someone please help. I would really appreciate it if someone can explain for me s12 qp23 Q5)C)

Oh this is easy, as its moles, my area. xD
So Mr = 90 and m = 0.6
n = 0.6/90 = 6.67*10^-3
1mol = 24dm^3
6.67*10^-3 = ?
= 160cm^3

 

[DESTROYER1198]

Oh this is easy, as its moles, my area. xD
So Mr = 90 and m = 0.6
n = 0.6/90 = 6.67*10^-3
1mol = 24dm^3
6.67*10^-3 = ?
= 160cm^3

thanx

 

[The Sarcastic Retard]

thanx

^_^

 

[Xaptor16]

15)
assuming the element as X, the equation will be X(NO3)2---> XO +2 NO2 + 0.5O2
moles of the nitrate equals the mole of the oxide formed
2/(X+ 14*2 +16*6) = (2-1.32)/(X+16)
solve for X and then match the Mr in the periodic table to find the element.

17)Find the moles of O2 using n=v/24 (don't forget to convert cm3 to dm3). Then write down the equations for the combustion of all the metals. Calculate the moles of all the metals using n=m/Ar. Then use mole ratios.

thankyou very much

 

[The Sarcastic Retard]

thankyou very much

Koi baath nai chori... Thought blocker here.... Hows chem?

 

[Xaptor16]

question 7, answer is C, but how do you know that?

25 Use of the Data Booklet is relevant to this question. 2.30 g of ethanol were mixed with aqueous acidified potassium dichromate(VI) and the desired organic product was collected by immediate distillation under gentle warming. The yield of product was 70.0%. What mass of product was collected?
A 1.54g
B 1.61g
C 2.10g
D 2.20g
answer is A, and I'm not getting that answer, I'm getting C...!

 

[Xaptor16]

Koi baath nai chori... Thought blocker here.... Hows chem?

what?! i thought you left XPC! and without a goodbye too!

 

[The Sarcastic Retard]

View attachment 52918

question 7, answer is C, but how do you know that?

25 Use of the Data Booklet is relevant to this question. 2.30 g of ethanol were mixed with aqueous acidified potassium dichromate(VI) and the desired organic product was collected by immediate distillation under gentle warming. The yield of product was 70.0%. What mass of product was collected?
A 1.54g
B 1.61g
C 2.10g
D 2.20g
answer is A, and I'm not getting that answer, I'm getting C...!

7) From the table you know X is element of group 3 with 3+ charge... Like AlCl3 it is XCl3

 

[The Sarcastic Retard]

what?! i thought you left XPC! and without a goodbye too!

Am back

 

[The Sarcastic Retard]

View attachment 52918

question 7, answer is C, but how do you know that?

25 Use of the Data Booklet is relevant to this question. 2.30 g of ethanol were mixed with aqueous acidified potassium dichromate(VI) and the desired organic product was collected by immediate distillation under gentle warming. The yield of product was 70.0%. What mass of product was collected?
A 1.54g
B 1.61g
C 2.10g
D 2.20g
answer is A, and I'm not getting that answer, I'm getting C...!

25)
Are u sure its A? M getting C as well.

 

[Xaptor16]

25)
Are u sure its A? M getting C as well.

yes i just checked again and its A! :/

 

[Xaptor16]

7) From the table you know X is element of group 3 with 3+ charge... Like AlCl3 it is XCl3

no but there isn't a large difference between the ionization energies between the 3rd and the 4th electron... there's a larger difference between the 5th and the 6th electron!

 

[Xaptor16]

Am back

so glad to hear it!

 

[The Sarcastic Retard]

no but there isn't a large difference between the ionization energies between the 3rd and the 4th electron... there's a larger difference between the 5th and the 6th electron!

Its like 850 then 900 then directly 2100 so its 3.
You have to see the first large change rather in the middle or last.

 

[The Sarcastic Retard]

yes i just checked again and its A! :/

I got it... Wait...