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Chemistry: Post your doubts here!

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15)
assuming the element as X, the equation will be X(NO3)2---> XO +2 NO2 + 0.5O2
moles of the nitrate equals the mole of the oxide formed
2/(X+ 14*2 +16*6) = (2-1.32)/(X+16)
solve for X and then match the Mr in the periodic table to find the element.
17)Find the moles of O2 using n=v/24 (don't forget to convert cm3 to dm3). Then write down the equations for the combustion of all the metals. Calculate the moles of all the metals using n=m/Ar. Then use mole ratios.
thankyou very much :)
 
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upload_2015-5-2_12-29-58.png

question 7, answer is C, but how do you know that?

25 Use of the Data Booklet is relevant to this question. 2.30 g of ethanol were mixed with aqueous acidified potassium dichromate(VI) and the desired organic product was collected by immediate distillation under gentle warming. The yield of product was 70.0%. What mass of product was collected?
A 1.54g
B 1.61g
C 2.10g
D 2.20g

answer is A, and I'm not getting that answer, I'm getting C...!
 
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View attachment 52918

question 7, answer is C, but how do you know that?

25 Use of the Data Booklet is relevant to this question. 2.30 g of ethanol were mixed with aqueous acidified potassium dichromate(VI) and the desired organic product was collected by immediate distillation under gentle warming. The yield of product was 70.0%. What mass of product was collected?
A 1.54g
B 1.61g
C 2.10g
D 2.20g

answer is A, and I'm not getting that answer, I'm getting C...!
7) From the table you know X is element of group 3 with 3+ charge... Like AlCl3 it is XCl3
 
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View attachment 52918

question 7, answer is C, but how do you know that?

25 Use of the Data Booklet is relevant to this question. 2.30 g of ethanol were mixed with aqueous acidified potassium dichromate(VI) and the desired organic product was collected by immediate distillation under gentle warming. The yield of product was 70.0%. What mass of product was collected?
A 1.54g
B 1.61g
C 2.10g
D 2.20g

answer is A, and I'm not getting that answer, I'm getting C...!
25)
Are u sure its A? M getting C as well.
 
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7) From the table you know X is element of group 3 with 3+ charge... Like AlCl3 it is XCl3
no but there isn't a large difference between the ionization energies between the 3rd and the 4th electron... there's a larger difference between the 5th and the 6th electron!
 
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no but there isn't a large difference between the ionization energies between the 3rd and the 4th electron... there's a larger difference between the 5th and the 6th electron!
Its like 850 then 900 then directly 2100 so its 3. :)
You have to see the first large change rather in the middle or last. :)
 
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