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Q 20 Cquestion 20 C? and q10 A?
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Q 20 Cquestion 20 C? and q10 A?
for Q 10 B and D are wrong as there is no change in oxidation state,C cant be correct as an acid must have H+ ions so A is the answerquestion 20 C? and q10 A?
In q20 you have to look for the longest chain. And in this qs longest chain contains 5 carbons. Start numbering from the carbon closest to the functional group so ans is CPlease can anybody help me with these question . I cant able to understand them. Question 20 in first screenshot and question 10 in the second one .thanks
Can you tell me the answers?
10 :A and 20:CCan you tell me the answers?
Ohhhhhh , righttttt , thanks man, good luck with your examsfor Q 10 B and D are wrong as there is no change in oxidation state,C cant be correct as an acid must have H+ ions so A is the answer
So its like a rule that we start measuring of carbon which is closest to the fuctional group. Thanks .In q20 you have to look for the longest chain. And in this qs longest chain contains 5 carbons. Start numbering from the carbon closest to the functional group so ans is C
In question 10 I know the answer B,C,D are wrong but i cant seem to understand how is A answer. Hso3- doesnt look like it is acting as a base. Correct me if i am wrong.for Q 10 B and D are wrong as there is no change in oxidation state,C cant be correct as an acid must have H+ ions so A is the answer
If you look at the 2nd eq, HSO3- accepts H+ which is a property of base ykSo its like a rule that we start measuring of carbon which is closest to the fuctional group. Thanks .
Guys do we have to wash the conical flask before performing the next titration or nah?
Went good expecting 31-32How was chem prac guys? If anyone else had the prac today , that is..
Woww nice I messed up a few parts but lets hope for the bestWent good expecting 31-32
My q1 n q3 went okay Alhamdulillah but i ran out of time so i couldnt really finish q2. I really hope i get marks in 30's thou xDit went gr8
tho lost one mark in q2 last part
rest was all okay
dwMy q1 n q3 went okay Alhamdulillah but i ran out of time so i couldnt really finish q2. I really hope i get marks in 30's thou xD
1. Cl2 + Mg ---> MgCl2 and 1/2 Cl2 + Na ---> NaCl
Thankyou got it1. Cl2 + Mg ---> MgCl2 and 1/2 Cl2 + Na ---> NaCl
Chlorine reacts with Mg to form MgCl2 bu reacts with Na to form NaCl. So twice the number of moles of Cl react with Mg (X) compared to Na (Y). This option is correct.
2. Again, Cl2 reacts with H2 to form 2HCl: Cl2 + H2 ---> 2HCl
and Chlorine displaces Br in KBr: 1/2 Cl + KBr ---> KCl + HBr
So twice the no of moles of Cl2 react with H2 compared to Kbr. So this option is also correct
3. Cl2 + 2NaOH ---> NaCl +NaCLO + H2O
3Cl2 +6 NaOH ---> 5NaCl + NaClO3 + 3H2O
In both of these reactions, Cl2 and NaOH react in the ratio 1:2. So the number of moles of Cl2 that react with 1 mol of X isn't twice the number of moles that react with Y. So this option is wrong. The ans is B
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