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correctI think 1 only, 3 is ridiculous and 2 is not correct since PV=nRT, R + n+ V are constant so temp increase increase pressure
again it is 1 only, because 3 means that pressure increase on both sides will be same, and 2 has same no. of moles on both sides of equation, however number 1 has 2 moles when equilibrium moves to RHS so increase in pressure will move the mercury up the right limbhelp.........
View attachment 62667 I need help with this. From March 2017 Paper 4 I only get 6 different carbon environments
View attachment 62667 I need help with this. From March 2017 Paper 4 I only get 6 different carbon environments

Isn't 6 and 7 the same?
Isn't 6 and 7 the same?


Thanks for the help, I understood it now.We should look beyond the immediate neighbors, 6 and 7 aren't exactly the same
The symmetry is at carbon 7, that is why 6 is the same as 6a and 5 is the same as 5a, but 7 is not the same as any of them
View attachment 62671
A simplified view of the molecule is shown before to hopefully explain the symmetry better, the symmetry is at carbon d.
View attachment 62672
I don't think you have to measure the exact spectra, your answer is right if you have taken your values from the Data Booklet.Someone please explain this to me. My answer was
-> Peak at 1670-1740 due to C=O
-> Peak at 3200-3600 due to RO-H
-> Peak at 2850-2950 due to C-H in alkane
I picked these range of wavenumber from Data booklet but mark scheme shows a different answer. For RO-H group, the absorption is 3200-3650 but data booklet shows 3200-3600... How do i measure the exact absorption from the spectra?
View attachment 62716
CAN ANYONE EXPLAIN HOW TO GET X AND Y?
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