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Chemistry: Post your doubts here!

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Capture.JPG I need help with this. From March 2017 Paper 4 I only get 6 different carbon environments
 
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help.........
again it is 1 only, because 3 means that pressure increase on both sides will be same, and 2 has same no. of moles on both sides of equation, however number 1 has 2 moles when equilibrium moves to RHS so increase in pressure will move the mercury up the right limb
 
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Isn't 6 and 7 the same?

We should look beyond the immediate neighbors, 6 and 7 aren't exactly the same

The symmetry is at carbon 7, that is why 6 is the same as 6a and 5 is the same as 5a, but 7 is not the same as any of them

Capture.PNG

A simplified view of the molecule is shown before to hopefully explain the symmetry better, the symmetry is at carbon d.

Capture2.PNG
 
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We should look beyond the immediate neighbors, 6 and 7 aren't exactly the same

The symmetry is at carbon 7, that is why 6 is the same as 6a and 5 is the same as 5a, but 7 is not the same as any of them

View attachment 62671

A simplified view of the molecule is shown before to hopefully explain the symmetry better, the symmetry is at carbon d.

View attachment 62672
Thanks for the help, I understood it now.
 
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Capture.JPG Capture.JPG Need help with i) and iii) from 42/M/J/16 . In i) The answer says "Asp having a charge of -2 and Val having a charge of -1" which I don't understand and in iii) The buffer pH is 12 but shouldn't it be pH 7 ?
 
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Capture.JPG Capture_1.JPG Need help with c) iv). Why are there 2 different structures? How would I know if mine is right?
 
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Someone please explain this to me. My answer was
-> Peak at 1670-1740 due to C=O
-> Peak at 3200-3600 due to RO-H
-> Peak at 2850-2950 due to C-H in alkane

I picked these range of wavenumber from Data booklet but mark scheme shows a different answer. For RO-H group, the absorption is 3200-3650 but data booklet shows 3200-3600... How do i measure the exact absorption from the spectra?
I don't think you have to measure the exact spectra, your answer is right if you have taken your values from the Data Booklet.
 
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Capture_x.JPG Capture_y.JPG Anyone know how to solve this question. I am mainly having trouble with how they set up the equationCapture_z.JPG. It's from 42/F/M/16.
 
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