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Chemistry: Post your doubts here!

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View attachment 62716
CAN ANYONE EXPLAIN HOW TO GET X AND Y?

First find out the volume of CO2 which is formed by the combustion....
volume of CO2 = 170-110 = 60 cm3

X = volume of CO2 / Volume of Alcohol
X = 60 / 20 = 3

Now find volume of water
Volume of Water = 250 - 170 = 80 cm3
Y / 2 = Volume of H2O / Volume of Alcohol
Y / 2 = 80 / 20 = 4
So Y = 8
 
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Capture_3.JPG Someone help me with this please? I have a problem with understanding what test 1 and test 5 is for . Also which test is for Amine and Amide here?
 
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Anyone please help me with V and W ? Shouldn't Oxygen be replace with O-H bond ? View attachment 62717 View attachment 62718

In this question test 1 is for the basic identification of whether the substance is an amide or amine. Since M does not react with the acid, this means that the substance must contain an amide group (it is neutral). Since the only other group we know containing nitrogen is amine, and it would react with the acid, we can safely assume the other substances all contain an amine group. In terms of test 5, it can test for either a hydroxy group, an acid, nucleophilic substitution or hydrolysis. remember that either an acid or an alkali can be used in hydrolysis. For the reaction with M, you should be able to see that the amide has hydrolysed into phenylamine and sodium propanoate.

EDIT: My bad, this is for the second question
 
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In this question test 1 is for the basic identification of whether the substance is an amide or amine. Since M does not react with the acid, this means that the substance must contain an amide group (it is neutral). Since the only other group we know containing nitrogen is amine, and it would react with the acid, we can safely assume the other substances all contain an amine group. In terms of test 5, it can test for either a hydroxy group, an acid, nucleophilic substitution or hydrolysis. remember that either an acid or an alkali can be used in hydrolysis. For the reaction with M, you should be able to see that the amide has hydrolysed into phenylamine and sodium propanoate.

EDIT: My bad, this is for the second question
Thanks for that
 
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Why is the percentage uncertainty in 1 C (ii) is 3?
I got 1%
 

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bro please help.... i have posted the question above this post..........
(0.5-0)/50 = 0.01 x 100 = 1%
We used the measuring cylinder to transfer 150cm^3 of Hydrogen Peroxide so each time there is an uncertainty of 1% . In this case , it's 3 times so it's 3%
 
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