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it was only out of two marks, right?
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r sure, can anybody remember the values all that were in the question so we can solve it again.No it was C5H10
thx, but u can exchange the 2C5H10 for C10H20?The question said that the moles of alkene were 0.01. Mass of oxygen was 2.4g and mass of co2 was 2.2g
Find the mole ratio and use it to find the alkene formula.
Moles of oxygen = mass/ molar mass = 2.4/32 = 0.075.
Moles of carbon dioxide = 2.2/44= 0.05.
When you simplify you get 1 : 7.5 : 5 which you multiply by 2 because ratio can't have decimal so the final ratio is
2: 15: 10.
The equation for the complete combustion is :
2C5H10 + 15O2 ---> 10CO2 + 10H2O
It was used because it consumes glucose and the enzymes in yeast break the glucose into ethanol and carbon dioxide. The number of yeast cells increase because the energy released by this breakdown of glucose allows the yeast to reproduce
the question was for two marksThe properties are correct but in this case, light is the important . You have to mention low density which makes it light. Also, resistance to corrosion is very important. If you wrote that it is light and malleable, you will get 1/3 marks
what if you only wrote the number of moles but not the ratio?The question said that the moles of alkene were 0.01. Mass of oxygen was 2.4g and mass of co2 was 2.2g
Find the mole ratio and use it to find the alkene formula.
Moles of oxygen = mass/ molar mass = 2.4/32 = 0.075.
Moles of carbon dioxide = 2.2/44= 0.05.
When you simplify you get 1 : 7.5 : 5 which you multiply by 2 because ratio can't have decimal so the final ratio is
2: 15: 10.
The equation for the complete combustion is :
2C5H10 + 15O2 ---> 10CO2 + 10H2O
it was HClWhat is another catalyst, other than yeast for the starch --> simple sugar thing?
Is it H2SO4..?
What is another catalyst, other than yeast for the starch --> simple sugar thing?
Is it H2SO4..?
what if you only wrote the number of moles but not the ratio?
do you lose all three marks?
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