Chemistry

[Ryan Huam]

1.00g of carbon is combusted in a limited supply of pure oxygen. 0.50g of the carbon combusts to form CO2 and 0.50g of the carbon combusts to form CO.

The resultant mixture of CO2 and CO is passed through excess NaOH(aq) and the remaining gas is then dried and collected.

What is the volume of the remaining gas? (All gas volumes are measured at 25 degree Celcius and 1 atmospheric pressure)

May I know how to solve this? The answer is 1dm3.

 

[sharase]

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[Zeldafar]

Chemistry is a fascinating discipline that empowers us to rankdle understand, manipulate, and transform the world at the molecular level. Its contributions span across a myriad of areas, from fundamental research to practical applications, driving innovation and improving our quality of life.

 

[jessica10199]

Step 1: Combustion of Carbon​

1. Combustion Reactions:
   • Carbon combusts to form carbon dioxide (CO₂): C+O2→CO2C+O2→CO2
   • Carbon also combusts to form carbon monoxide (CO): 2C+O2→2CO2C+O2→2CO
2. Given Data:
   • Total carbon = 1.00 g (papa's games)
   • Carbon forming CO₂ = 0.50 g
   • Carbon forming CO = 0.50 g
3. Molar Mass:
   • Molar mass of carbon (C) = 12.01 g/mol
   • Molar mass of CO₂ = 44.01 g/mol
   • Molar mass of CO = 28.01 g/mol

Step 2: Moles of Carbon​

• Moles of carbon combusted to form CO₂: Moles of C=0.50 g12.01 g/mol≈0.0417 molMoles of C=12.01g/mol0.50g≈0.0417mol
• Moles of carbon combusted to form CO: Moles of C=0.50 g12.01 g/mol≈0.0417 molMoles of C=12.01g/mol0.50g≈0.0417mol

Step 3: Moles of Gases Formed​

1. Moles of CO₂ formed:
   • From 0.0417 mol of carbon: Moles of CO2=0.0417 molMoles of CO2=0.0417mol
2. Moles of CO formed:
   • From 0.0417 mol of carbon: Moles of CO=0.0417 molMoles of CO=0.0417mol

Step 4: Total Moles of Gas​

• Total moles of gas before passing through NaOH: Total moles=0.0417 mol (CO₂)+0.0417 mol (CO)=0.0834 molTotal moles=0.0417mol (CO₂)+0.0417mol (CO)=0.0834mol

Step 5: Reaction with NaOH​

• NaOH will react with CO₂ to form sodium carbonate (Na₂CO₃) and remove it from the gas mixture: CO2+2NaOH→Na2CO3+H2OCO2+2NaOH→Na2CO3+H2O
• Since all CO₂ is absorbed, only CO remains in the gas mixture.

Step 6: Remaining Gas​

• Moles of CO remaining after reaction: Moles of CO remaining=0.0417 molMoles of CO remaining=0.0417mol

Step 7: Volume of Remaining Gas​

• Using the ideal gas law, at 25°C and 1 atm, 1 mole of gas occupies approximately 24 dm³.
• Volume of remaining CO: Volume=Moles×24 dm3/mol=0.0417 mol×24 dm3/mol≈1 dm3Volume=Moles×24dm3/mol=0.0417mol×24dm3/mol≈1dm3

Conclusion​

The volume of the remaining gas (CO) after passing through excess NaOH is approximately 1 dm³.