CHOLESTEROL chiral centre

[hassam]

it was +1 -1....those who were nt agreeing...take this .....ur........
Potassium permanganate (KMnO4) is a very strong oxidant able to react with many functional groups, such as secondary alcohols, 1,2-diols, aldehydes, alkenes, oximes, sulfides and thiols. Under controlled conditions, KMnO4 oxidizes very efficiently primary alcohols to carboxylic acids
source http://en.wikipedia.org/wiki/Oxidation_ ... ylic_acids
be sure to read

 

[ahmed t]

yea teach them a lesson hassam

 

[sweetiepie]

yeahhhhhhh i rote it corect...

 

[WellWIshER]

yeahhhhhhh i rote it corect...

FLUKE !!

 

[sweetiepie]

nooo..

 

[kakarocks]

YAY :Yahoo!: i got it right [Guesswork]

 

[hassam]

u say wikipedia says/....wrong....so go................... :evil: :evil: =@ ...

 

[kakarocks]

Btw what was the answer to The ammonium ion structure and the enthalpy change ?

 

[Zishi]

u say wikipedia says/....wrong....so go................... :evil: :evil: =@ ...

Wikipedia doesn't say that it oxidises them under cold, and dilute conditions. I also wrote +1 and -1. But the thing is if that was the case that the OH group had to be oxidised under those conditions, then the di-ol that formed, one of its OH group would've also been oxidised. But KMnO4 just oxidises them to diol - not further than that. So those who wrote +2 and -1 are correct. Our answers are sadly wrong, hassam.

 

[BILALrox01]

What ever.. I wrote +2 and -1 but Hassam does have a point.. anyways it all depends on the examiners.

 

[hassam]

but zishi if cold cn oxidise alkene............then how on earth it cnt oxidise....alcohol group....

 

[hassam]

well zishi....i hv cnfromed form A LEVEL CHEMISTRY by e.n ramsden...that watever the conditions are...the only thing needed is acidifiy...it cn oxidise both primary and secondary and its 100 percent...any doubt....remainng zishi u cn chek that book by en ramsden....and if u hav any doubt abt acidification thing....than keep in mind if not acidified then alkene cn also NOT be oxidised....its +1 and -1 bilalrox...100 percent i showed u wikipedia and now en ramsden...which says only acidification

 

[Zishi]

well zishi....i hv cnfromed form A LEVEL CHEMISTRY by e.n ramsden...that watever the conditions are...the only thing needed is acidifiy...it cn oxidise both primary and secondary and its 100 percent...any doubt....remainng zishi u cn chek that book by en ramsden....and if u hav any doubt abt acidification thing....than keep in mind if not acidified then alkene cn also NOT be oxidised....its +1 and -1 bilalrox...100 percent i showed u wikipedia and now en ramsden...which says only acidification

Page number, and paragraph?

Well, I've read the topic about alkenes from EN Ramsden again, and it has only discussed about oxidation under alkaline conditions(in which potassium permanganate is a weak oxidising agent). Maybe you read from a different page number or other edition of that book - I've 4th one, which one do you have? The thing is also that if in cold, and dilute it could oxidise alcohols, then a diol would've been never formed.

 

[hassam]

chek alcohol chapter oxidation topic.....and if u say +2 +1......then +1 is WRONG...cos it shud be zero...k and check en ramsden

 

[hassam]

http://www.cliffsnotes.com/study_guide/ ... 23272.html
chek this...page it shows oxidation of secondary alcohol...so it cn never be +1 in second place...not on earth probably in heavensss

 

[Zishi]

chek alcohol chapter oxidation topic.....and if u say +2 +1......then +1 is WRONG...cos it shud be zero...k and check en ramsden

I never said +2 and +1. I said, like others said, it's +2 and -1. The question didn't mix the cold, dilute solution with hot, conc. one, they were put in different containers with cholesterol to do different reactions. I don't understand why I'm arguing on it. Sorry, but I'll stick to my answer - it's been confirmed, plus I've not found any clue about it in EN ramsden. I don't want to waste time just discussing a paper which is OVER now. :roll:

 

[sweetiepie]

hmm lsn telme da answer for that graph xy z wat was da answer plzz reply me...

 

[Hateexams93]

hhh... i wrote +2 and O ...so its wrong ? :/ did i get at least one Q right =.= my answers r different as usual

 

[sweetiepie]

reply my question wat did u rite...

 

[Hateexams93]

higher lower lower