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bro which language u have learnt for tomorrow paper?Easy...just add a Decision box after input no of years...and a attempts variable before it...then after in valid increment the attempts variable connecting to decision box...
VB6.....its almost written same as the pseudocode..bro which language u have learnt for tomorrow paper?
To fully understand what this function does, you need some basic knowledge about number theory (an extensive branch of mathematics). A recursive solution for calculating gcd (greatest common divisor) of two numbers is based on the concept of Euclidean Algorithm, which was stated (and proven) by Euclid in his book "Elements". This states that if you take the remainder of a with respect to b (assume that a and b are two numbers and a > b), then the gcd of the smaller number (b) with respect to this remainder (i.e. a MOD b) is equal to the gcd of a and b. You successively perform this computation until you reach a stage when the remainder is 0 i.e. two numbers (n, 0). Now, the gcd of 0 and any other number is the other number. That is the gcd of the initial two numbers.Can anybody explain question 4 of oct/nov 2013..URGENT!!!
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Computing (9691)/9691_w13_qp_22.pdf
To fully understand what this function does, you need some basic knowledge about number theory (an extensive branch of mathematics). A recursive solution for calculating gcd (greatest common divisor) of two numbers is based on the concept of Euclidean Algorithm, which was stated (and proven) by Euclid in his book "Elements". This states that if you take the remainder of a with respect to b (assume that a and b are two numbers and a > b), then the gcd of the smaller number (b) with respect to this remainder (i.e. a MOD b) is equal to the gcd of a and b. You successively perform this computation until you reach a stage when the remainder is 0 i.e. two numbers (n, 0). Now, the gcd of 0 and any other number is the other number. That is the gcd of the initial two numbers.
But you don't require this knowledge to attempt the question. Just follow the logic. I elaborated just because you asked.
Can you simplify more.Easy...just add a Decision box after input no of years...and a attempts variable before it...then after in valid increment the attempts variable connecting to decision box...
Sorry for bad handwriting but this is ho i did...do notice that as in this question the examiner didn't gave any space i did cut a printed line ...as there was no other way..: p...Can you simplify more.
Thx for helping but i didn't understood a single word...probably this wont come again so I'm in a chill mood.......JUST pray paper would be easy...To fully understand what this function does, you need some basic knowledge about number theory (an extensive branch of mathematics). A recursive solution for calculating gcd (greatest common divisor) of two numbers is based on the concept of Euclidean Algorithm, which was stated (and proven) by Euclid in his book "Elements". This states that if you take the remainder of a with respect to b (assume that a and b are two numbers and a > b), then the gcd of the smaller number (b) with respect to this remainder (i.e. a MOD b) is equal to the gcd of a and b. You successively perform this computation until you reach a stage when the remainder is 0 i.e. two numbers (n, 0). Now, the gcd of 0 and any other number is the other number. That is the gcd of the initial two numbers.
But you don't require this knowledge to attempt the question. Just follow the logic. I elaborated just because you asked.
thanks but wo last part zyada samaj me nahi ayaSorry for bad handwriting but this is ho i did...do notice that as in this question the examiner didn't gave any space i did cut a printed line ...as there was no other way..: p...
if you in chem and bio..Thx for helping but i didn't understood a single word...probably this wont come again so I'm in a chill mood.......JUST pray paper would be easy...
how was yours?Guys how was ppr..??:/
guys dont discuss the paper till next day! otherwise u will get banned as moderators say!I think it was the toughest paper till now...before there was a format that u atleat got 15 to 20 marks definations...but in this ppr there wasnt a single defination.....what do you think threshold will be for p2...only p1 can save me nw..m expecting 69/70 in p1...and 45+ in p2
This isn't discussion about paper just wz knowing how ppr went...guys dont discuss the paper till next day! otherwise u will get banned as moderators say!
mine went normal! I hope i get a B minimum!This isn't discussion about paper just wz knowing how ppr went...
I don't know about the centre but till my friends are concerned no one did well...i think threshold will be till 40...But we should do the rest paper talking tomorrow after 24 hrs..mine went normal! I hope i get a B minimum!
how ur went? what was the overall atitude of people at ur center who gave it?
no minimum gt will be 43 or 44... i am sure!I don't know about the centre but till my friends are concerned no one did well...i think threshold will be till 40...But we should do the rest paper talking tomorrow after 24 hrs..
now we all can talk!!!no minimum gt will be 43 or 44... i am sure!
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