- Messages
- 9
- Reaction score
- 1
- Points
- 3
please guys help me with S1 and C2
We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
Help plz solve this step by step, I can't integrate this, need help
no u cannothey guys, I'm pretty new to the forum. Do you think I can finish the syllabus in 4 months and sit for the exam in O/N-13 session?(I have zero knowledge of the syllabus)
Taking velocity=0 and solving for t, yields, t=0.655. putting it in the equation of x yields, x=-1. At fixed point A, acceleration=0. So at initial point, x=12. so difference from fixed point to point where v=0 is the amplitude.{12-(-1)}=13.Can someone please explain to me how you read of the amplitude from the given information. Thanks
hey guys, I'm pretty new to the forum. Do you think I can finish the syllabus in 4 months and sit for the exam in O/N-13 session?(I have zero knowledge of the syllabus)
To all the brave and perhaps lunatic guys who took Further Mathematics, I believe we should all be more regular in this thread. Further Mathematics is considered as the most difficult subject of A levels but if we all try together and help one another we could reduce the difficulty. No matter if there are 5 people studying this subject, I request all of you to regularly and actively participate in this thread so that we can ask questions to one another and have them quickly solved. Please visit this thread at least twice a day, ask questions if you face problem and answer others' questions if you know. That way all of us will be benefited. Ex- Lecom40 asked a question on May 5th and it was answered on May 24th. That's unexpected. If you could be regular he would have had his answer a long time back. So I once again ask all of you to help each other and make this thread an active one, please.
Thanx a lot Sakib. I desperately needed that information. I don't have the book you mentioned but I have the book Mechanics for A level Bostock and Chandler (the green book). However I have found the two formulas on wikipedia http://en.wikipedia.org/wiki/Centroid#By_integral_formula.If you have "Mathematics-Mechanics and Probability" by Bostock and Chandler see chapter 15(pg-514). It has an excellent explanation to find centroid using Integration. As it shows, the formula varies depending on the shapes. Generally formula is, for X coordinate, {integration of (xy)dx}/Area under curve, and for Y coordinate, {integration of (.5y^2)dx/Area under curve}. But as I have already said, formula varies depending on the shape and even limits. O/N 10 p1 Q 3.
For 3D shape, X coordinate= {integration of (pie*x*y^2)dx/volume of shape}. Generally the curve is rotated about the x-axis, hence Y-coordinate is 0.
Tension in the string, Radially inwards, Component of weight(at the position where OP makes an angle of (π/3) with the upward vertical), also radially inward. But I could not show (ii) of the same question. Somebody help me.
It surely will, but is d^2@/dt^2 accelaration? In the question d@/dt is given which is angular velocity. Using v=wr, where w=angular velocity, find the velocity(l sin@). Then find the tangential(dv/dt) and radial component(v^2/l) of acceleration and pythagoras yields the resultant acceleration which is also l sin@. So magnitude same.June 09 P 2 No 1.
I don't get that transverse acceleration. Shouldn't differentiating d@/dt once give you d^2@/dt^2?
Where @ : theta.
It surely will, but is d^2@/dt^2 accelaration? In the question d@/dt is given which is angular velocity. Using v=wr, where w=angular velocity, find the velocity(l sin@). Then find the tangential(dv/dt) and radial component(v^2/l) of acceleration and pythagoras yields the resultant acceleration which is also l sin@. So magnitude same.
Note- Be careful when calculating dv/dt. If you find dv/dt= l cos@ (which I did initially and it took me an hour to realize it) you are wrong.
BTW, what test?
v=l sin@, means, v is expressed in terms of @. So, dv/dt has to be calculated by chain rule(O level differentiation). dv/dt=(dv/d@)*(d@/dt). What you calculated is dv/d@. d@/dt is sin@, as given in the question.So, dv/dt=l cos@ sin @. Hope that answers it.
About that trust thing, that's one lesson everyone learns first hand. I haven't yet been in such a situation so far and I hope I never have to.
Back to Further Mathematics, O/N 04, P-2, Q-11 Either. The whole question has baffled me. But I guess, if anyone could solve (i) for me, I may be able to proceed. So anyone?
For almost 10 years, the site XtremePapers has been trying very hard to serve its users.
However, we are now struggling to cover its operational costs due to unforeseen circumstances. If we helped you in any way, kindly contribute and be the part of this effort. No act of kindness, no matter how small, is ever wasted.
Click here to Donate Now