Further Mathematics: Post your doubts here!

[DragonCub]

I have just finished my A2 and I am planning to take Further Mathematics study by myself...So friends please help me....
Where can I find necessary course materials to study FM? Are there any text books particularly for FM? Xtremepapers can help me with the past question papers, but i need to learn the course materials...please help me

The tension can be zero since at this point weight provides the entire centripetal force. As long as the circular motion is maintained, it is okay.

 

[usman123]

HI can anyone solve this question nov 7 Q 11 (Either) http://www.xtremepapers.com/papers/...athematics - Further (9231)/9231_w07_qp_2.pdf

 

[OakMoon!]

HI can anyone solve this question nov 7 Q 11 (Either) http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics - Further (9231)/9231_w07_qp_2.pdf

Here's the first part. I have skipped the detail of finding the angles. I hope you get that. And I'll post the second part soon.

 

[OakMoon!]

Here's the second part:

 

[usman123]

thanks

Here's the second part:

View attachment 8458

 

[usman123]

I also need help in Question 11 (Either) of June 07 paper 2
http://www.xtremepapers.com/papers/...athematics - Further (9231)/9231_s07_qp_2.pdf

 

[Executor]

Ok i dont mean to do spam or anything but please go to the following thread and make dua for all of us :
http://www.xtremepapers.com/community/threads/dua-for-all-candidates.14272/

Dont forget to share and Remember every share makes a difference

 

[salmanAamer_66z]

Can somebody please post the solution of June 06 P2 Question 4 regrading moment of inertia on line . I am really having a hard time solving its second part

 

[MW24595]

It's easy. Slice the shape into 3 rectangular laminas. Find the moments of inertia for each of them about their centers. And then use the Parallel axis rule to find each lamina's moment of inertia about A. Add all of them up, and I'm guessing that'll be your answer.

 

[Sajana Meddaduwage]

Please guys a big favour upload some notes on rotation of rigid body please...

 

[MurtazaRangwalla]

Hey guys . Could someone please explain to me how M10/13 Question 5's second part is done?
http://www.xtremepapers.com/papers/...thematics - Further (9231)/9231_s10_qp_13.pdf

Much appreciated

 

[allysaleemally]

Please could anyone help me in oct/nov 2011 m1 v3 question 6, I really need your help!
http://www.xtremepapers.com/papers/...S Level/Mathematics (9709)/9709_w11_qp_43.pdf
marksheet: http://www.xtremepapers.com/papers/...S Level/Mathematics (9709)/9709_w11_ms_43.pdf


Thanks a million!

 

[usman123]

Can anyone solve this question. Paper 2 Novemeber 2006 question 2 and 3 Please help
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics - Further (9231)/9231_w06_qp_2.pdf I need immediate help can somebody help me!!!!!!!!!!!!!!!!!!!!!!

 

[Saquib]

Someone May June '11 - paper 21, question no. 2 HELP PLEASE!!!



Edit: Problem solved, no need to reply! Thanks anyway!!!

 

[DragonCub]

I also need help in Question 11 (Either) of June 07 paper 2
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics - Further (9231)/9231_s07_qp_2.pdf

The first part


The second part


The third part
F1 = mg cos θ - f
It is sure that F1 ≤ mg and that cos θ ≤ 1
Deduced that f ≥ 0
So R ≥ 0. There must be contact.

 

[Skywalker]

How long does it take to complete the Further Maths syllabus?

 

[MW24595]

That depends on how hard you're willing to work, how much help you have, and how good you are.

Anyway, how does one derive the expression shown in Q11 (Mechanics) from Oct/Nov 2006? I keep deriving offshoots of it, but never exactly that.

 

[DragonCub]

Anyway, how does one derive the expression shown in Q11 (Mechanics) from Oct/Nov 2006? I keep deriving offshoots of it, but never exactly that.

It's very simple if you use conservation of energy.

 

[MW24595]

It's very simple if you use conservation of energy.
View attachment 9785

Ow, crap. Sorry, I made a mistake. I meant Q 11 (Mechanics) from Paper 2 October/November 2007. :/ But thanks for replying anyway.

 

[usman123]

It's easy. Slice the shape into 3 rectangular laminas. Find the moments of inertia for each of them about their centers. And then use the Parallel axis rule to find each lamina's moment of inertia about A. Add all of them up, and I'm guessing that'll be your answer.

I also have problem in this question can you post the solution online it would be so nice of you please