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Here you go!CIE 2008 may-june Q.11 (differential equation)
please help me solve both part of the question
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Here you go!CIE 2008 may-june Q.11 (differential equation)
please help me solve both part of the question
Here you go!hi guys,
i've been working on momentum and impulse,but i'm getting some difficulty concerning coeff. of restitution on inclined planes.
here's an example:
A ball drops vertically onto a smooth plane inclined to the horizontal at an angle α. It hits the plane
with speed 8ms−1 and rebounds horizontally. The coefficient of restitution between the ball and the
plane is 1/3.
Find the value of α and the speed with which the ball rebounds.
(j06/1)
i would really appreciate it if anybody could help me out with this question.
thanks.
thanks a lot.Here you go!
I need urgent help! Can some1 give me the names of the best books for Cie further maths! Do any1 know any online tutors for further maths?? I m dying here guys. I have NO teachers and NO books for Further maths here! Guys please help, its urgent!!! I have to bring books and need an online tutor immediately! :'(
First step is to let y = the roots in terms of x for the new equation, then rearrange until you have x in terms of y. Sub the x into the old equation and voila! The second part just involves finding S.O.R., P.O.R. etcHi guys,i'm getting some difficulty in roots of polynomial equations as i've just started this new chapter.
i'm stuck on this question.i would really appreciate some help.thanks.
The roots of the equation x^3 + x + 1 = 0 are α, β, γ . Show that the equation whose roots are
4α + 1/α + 1,
4β + 1/β + 1,
4γ + 1/γ + 1
is of the form
y^3 + py + q = 0,
where the numbers p and q are to be determined.
Hence find the value of
(4α + 1/α + 1)^n + (4β + 1/β + 1)^n + (4γ + 1/γ + 1)^n
for n = 2 and for n = 3.
(nov06/6)
thanks again.First step is to let y = the roots in terms of x for the new equation, then rearrange until you have x in terms of y. Sub the x into the old equation and voila! The second part just involves finding S.O.R., P.O.R. etc
take 2^2 common and apply the sum of squares method.Q4. Last part which involves 'applying sum of squares to obtain result'. I'm unable to see how 2^2 + 4^2 + ....+ (n-1)^2 = the given result.
taking derivative: 3x^2 + 3(y^2)y'=3y + 3xy' (1) (cut the 3s out)can any one do Q10 oct/nov2012/13
there is a separate thread for maths 9709 so please post it there. This is for further maths.heey guys can someone help me with this http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_qp_43.pdf
the first question plzz and question 3 part 2
thanks in advance
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