Guys any tips for Maths Paper 42???

[My Name]

http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s12_qp_42.pdf
question 11 part b
Awesome12
http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w13_qp_41.pdf
question 3 b
THANKU

 

[silver_moon]

View attachment 42082
Awesome12 Can you briefly explain how will we do this on the graph? the left part pf the equation is the graph's eqn.

first..u need 2 find d equation 10-5x by substituting d x n y values n draw d straight line aftr plottin 3 points..aftr dt u c wr d 2 equation lines meet each odr n dts d answer...dr cud b mor dn 1 ansr..hop dis ans helped u!

 

[Ameena Eesa]

first..u need 2 find d equation 10-5x by substituting d x n y values n draw d straight line aftr plottin 3 points..aftr dt u c wr d 2 equation lines meet each odr n dts d answer...dr cud b mor dn 1 ansr..hop dis ans helped u!

but its only for one mark. plus, i guess the eqn would be y=10-5x?

 

[silver_moon]

but its only for one mark. plus, i guess the eqn would be y=10-5x?

is dis igcse r o level question..nywy dis is d method u hav 2 do

 

[Elfenlied]

CAN SOmeone please help me with May/June 2013 paper 42 question 11 (i) (ii) (iii) (c)

 

[Mavilda Bucket]

freq density = freq/class width
try to apply here, it doesn't work :/

idk which ppr is it?how to check

cn u tme d ppr?

 

[Mavilda Bucket]

See calculate the frequency density for 60-80
It is 0.7
However on the histogram, they have made it 2.8
thus the ratio is
0.7 : 2.8

For example for the group 120-150
f.d = 32/30
= 1.0667

Thus on the histogram, it will be

0.7 : 2.8
1.0667: x

Cross multiply and find x. Do this for the other values

y cant we simply find using d ratio of freq:height?

 

[Awesome12]

y cant we simply find using d ratio of freq:height?

Well we were supposed to do that, but the question itself states that for a f.d x, the height drawn will be y, and thus we need to keep this ratio constant

 

[Mavilda Bucket]

can u pls show m dis Awesome12

 

[Mavilda Bucket]

5 (a) 27/x, as imagine you have spent $10 on toffees. Each toffee costs $x ( lets say $2). Thus you will have 10/2 = 5 toffees
(b) 25/x-2, as stated above
(c) View attachment 42076

how u got 6, 4*2=8

 

[Awesome12]

how u got 6, 4*2=8

There is 2x on the left side. Thus -8x+2x = 6x

 

[silver_moon]

can u pls show m dis Awesome12
View attachment 42086

ita act. simple..first u need 2 substitue 2 values for n..4 example 2 and 3 dn u wud get a imultaneousequation..nw u cn easily find a and b.
a x 2cube+b x 2cube+ 2/6=5 and a x 3cube+b x 3cube+ 3/6=14..so nw simplify it n sove the equation....i hope u got it

 

[tottybee3]

Firstly, xy=5cm2, therefore y=5/x .
Then, Y(x+2)=6, so Y=6/(x+2).

According to that, y+Y=1 will become (5/x) + (6/(x+2)) = 1.

After that taking the LCM of the fractions, we will get (5x+10+6x)/(x^2 + 2x) =1

Simplifying that, (11x + 10)/(x^2 + 2x) = 1.

Take the denominator over to the other side, making 11x + 10 = x^2 + 2x

Move everything over to the other side: x^2 + 2x - 11x -10 = 0

Upon simplifying, you will finally get x^2 -9x -10 = 0

Hope I helped!

thank u very much

 

[Mavilda Bucket]

ita act. simple..first u need 2 substitue 2 values for n..4 example 2 and 3 dn u wud get a imultaneousequation..nw u cn easily find a and b.
a x 2cube+b x 2cube+ 2/6=5 and a x 3cube+b x 3cube+ 3/6=14..so nw simplify it n sove the equation....i hope u got it

y a i got...thanx loadz

 

[Mavilda Bucket]

 

[silver_moon]

There is 2x on the left side. Thus -8x+2x = 6x

guys don forget to lrn all d formulae n know hw to describe all d angles(interior,alternate and allied)

 

[silver_moon]

View attachment 42136
View attachment 42137
can any one please help me with b(II) i get it wrong everytime

aftr knowin dt AB is 6cm u hav to use d similarity rule so u'll do 4/6*18.9..dts d ans..if u din ndrstand dn let me know..plzz

 

[iamservantofALLAH]

Will someone be kind enough to upload a picture solution of Question 2(a) of paper 0580/43/M/J/13?

 

[Akshajistari]

You use the scale factor formula so :

k= distance 1/ distance 2

k=6/4

k= 1.5

k = total distance 1 / total distance 2

you need to find distance 2, so

total distance 2 = total distance 1/ k

total distance 2 = 18.9/ 1.5

total distance 2= 12.6 km

OR
You could use the cosine rule to find the third unknown length of the triangle and then adding all the sides together to find the total distance walked.

a^2 = b^2 + c^2 - 2bccosA

LOL I'm kinda lazy so I'l just tell you to do the rest yourself

 

[slisjunknown]

guys don forget to lrn all d formulae n know hw to describe all d angles(interior,alternate and allied)

What are allied angles??????????