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guys plz help!!!chem s09_qp3.plz help!!

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here's the link
page 8....question 5b...cant figure it out .. :unknown: :unknown: .how to you get the formula????????plz help guys!!!!!!!!!!

thanks in advance!
 
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i figured out the answer but it is sooo hard and i think ill try my best to explain it to u :D
first we write down the equation
the we solve for the mole (something related to math)
then we find the ratio of the mole of the reactant and product
then we substitute them in the equation.
after that balance the equation by putting number for the element (dont change the mole number)

hope u got it :D
 
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haochen said:
look at my previous post :D

awesome explanation!!!!! :fool: (no offense)
quite honestly it didnt HELP AT ALL!!!!i also knew that first we have to.....than...than this,....then that....uuurrrggghhh!!!!!!
anyways u tried ur best dude...thanks....see ya around.. :wink:
 
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haochen said:
ok thx for telling :(

hey dude dnt b sad.....i didnt mean 2 hurt ya feelings.....at least u understood the question...i even couldnt do that.....nd u posted in this thread with ur best efforts...nobody did that.....chill out.. :)
 
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I have seen many people ask about Question 5.b)

So, I thought I would explain it to everyone here :p

From the graph, 8cm^3 of the Phosphate reacts fully with 12cm^3 of T Nitrate.

So, identifying only the atoms we need:

T : Phosphate

Taking a ratio of volumes:

8 : 12

Multiply to find the LCM of both sides.

3T : 2 Phosphate

=> Equal volumes:

24 : 24.

This implies that the formula is T3(PO4)2
 
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The way haochen said also applies, I just thought that this way was easier :p
 
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thanks...it helped a lot...nd u ""thought"' this way was easier(lol no offense again to haochen)
thank u both of u....keep up da gd work... :good:
 
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haochen said:
i figured out the answer but it is sooo hard and i think ill try my best to explain it to u :D
first we write down the equation
the we solve for the mole (something related to math)
then we find the ratio of the mole of the reactant and product
then we substitute them in the equation.
after that balance the equation by putting number for the element (dont change the mole number)

hope u got it :D

Can you please do it on paper and upload that! :)
 
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For question paper 2009 Q9 b
Where did you get 8 from?
doesnt it react fully with 6cm^3? because from then on its constant?
 
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Unkownbunny said:
For question paper 2009 Q9 b
Where did you get 8 from?
doesnt it react fully with 6cm^3? because from then on its constant?

See the graph carefully.... :) Its on 8 cm^3
 
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