Help Answer This Electromagnetism Physics P4 Question

[syazapion]

Q: Electrons are accelerated a potential difference of 220V. They then pass into a region of uniform magnetic flux of flux density 0.54mT.
The path of the electrons is normal to the magnetic field. Given that the charge on the electron is 1.6x10^(-19) C and it's mass is 9.1x10^(-31) Kg.
Calculate the speed of the accelerated electron.

A: 8.8x10^6 ms^(-1) <--- BUT HOW CAN YOU GET THIS ANSWER?? Please....Anyone. D8

 

[musa]

put 1/2mv^2=QV where
m is mass
v is speed
Q is charge
and V is voltage

 

[yasser37]

Electric energy = Kinetic Energy
Qe = 0.5 m v^2
v= root(2qw/m)


you'll get the answer

 

[syazapion]

OH COOOL! THANKS YOU GUYS!! Best of luck on you exams!