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Welcome ... and the graph alone was 3 marks ...Thank you mate for motivating me, any ideas of howmany marks it had?
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Welcome ... and the graph alone was 3 marks ...Thank you mate for motivating me, any ideas of howmany marks it had?
I think my answers to that whole question was wrong ... But someone had answers? I really want them.Can we three discuss with each other? in pm?
For Q2I think my answers to that whole question was wrong ... But someone had answers? I really want them.
For Q2
Q2 17.2 speed at 3.0s distance was 22.7,displacement 7.33 vertically down
Graph of velocity was a straight line with negative gradient with x intercept at 1.25 and y intercept at 12.2 and on the other side at the end at 3 s it was -17.2
15 people voted for threshold to be 50-60 damn guys.. Easy on the GT..
Speed at 1.25 was 0.All force due to gravity.Total time travelled down was (3.0-1.25) i.e 1.75How did you calculate the speed?
Thank you... I think i got distance right :/For Q2
Q2 17.2 speed at 3.0s distance was 22.7,displacement 7.33 vertically down
Graph of velocity was a straight line with negative gradient with x intercept at 1.25 and y intercept at 12.2 and on the other side at the end at 3 s it was -17.2
But the total distance downwards will not be equal to 3-1.25 coz s is -ve after 2.5 ... so the ball is rebounding at t=2.5s ... rite?Speed at 1.25 was 0.All force due to gravity.Total time travelled down was (3.0-1.25) i.e 1.75
then we just input using v=u + at
where u is 0,a is 9.81 and t is 1.75
This gives 17.16 i.e 17.2
For distance i did 1/2 x 9.81 x 2.5(sq) + 1/2 x 9.81 x 0.5(sq).. Did anyone else do that?
No its not rebounding its going downwards.If it went to displacement would've changed.Think of it like we threw it over a hole.To a point it rose above it,then it kept falling and went into the hole,even below the point where it first started.Thats where DISPLACEMENT got negative.B
But the total distance downwards will not be equal to 3-1.25 coz s is -ve after 2.5 ... so the ball is rebounding at t=2.5s ... rite?
So ur telling the stone sunk into the ground ... I actually considered the possibility but didn't have time to thinkNo its not rebounding its going downwards.If it went to displacement would've changed.Think of it like we threw it over a hole.To a point it rose above it,then it kept falling and went into the hole,even below the point where it first started.Thats where DISPLACEMENT got negative.
Not necessarily.There are loads of scenarios.This could also be the case that we threw it over on the edge of a cliff and it went up and kept going down,all vertically,understand?If it rebounded,it would show displacement would not be negative as the stone would not go below its initial pointSo ur telling the stone sunk into the ground ... I actually considered the possibility but didn't have time to think
lol it didn't exactly sink into the ground, it was most probably thrown from above ground level.So ur telling the stone sunk into the ground ... I actually considered the possibility but didn't have time to think
Oh ok kinda getting it it ... But if I could have a look at the question it would become more clear ...Not necessarily.There are loads of scenarios.This could also be the case that we threw it over on the edge of a cliff and it went up and kept going down,all vertically,understand?If it rebounded,it would show displacement would not be negative as the stone would not go below its initial point
But it could be a scenario ... if the ground is sand that islol it didn't exactly sink into ground, it was most probably thrown from above ground level.
That would obviously slow the ball down and besides it said AIR RESISTANCE is negligible.The friction due to sand would be immense and create a weird non-parabolic graph.But it could be a scenario ... if the ground is sand that is
The point is it went below the point from which it was thrown. Now it could have been a cliff, a hole, or anything else. It doesn't really matter.But it could be a scenario ... if the ground is sand that is
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