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I think you should also mention why it is the biggest. Due to most number of electrons/electron shells.i wrote the same thing
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I think you should also mention why it is the biggest. Due to most number of electrons/electron shells.i wrote the same thing
you can draw both this isnt inter board but it is better for pencil. read instruction you CAN use pencils for diagrams and graphs etcthanks man . My heart was in my throat when someone told me you had to draw em in pen![]()
Humm...is the question asking about double bond or pi bond? Only Group IV elements can form pi bonds due to sp3 hybridizationi hope for phosphprus too xD XD
dude y take risk with carbon when you know oxygen has a double bond -_-
http://chemistry.about.com/od/chemistryglossary/g/Pi-Bond-Definition.htm check thisHumm...is the question asking about double bond or pi bond? Only Group IV elements can form pi bonds due to sp3 hybridization
Al & Be reacts with water to form hydrated ions. Not sure if HCl is covalent.Guys I wrote Na :/ not appreciating that a co-valent chloride was asked :/ and Al is wrong . I collected from diff Mark schemes that Na and Mg dissolve in water but Al to S all chlorides react!
It was v.v.tricky H seems to fit all the conditions, many of us would not even think of that!
i hope for phosphprus too xD XD
dude y take risk with carbon when you know oxygen has a double bond -_-
H is the only correct answerAl & Be reacts with water to form hydrated ions. Not sure if HCl is covalent.
both are correctwhat was the question for the pi/double bond?
I think i either wrote N or O.
dont argue over chem the only subject i will never admitt defeat on xDAl & Be reacts with water to form hydrated ions. Not sure if HCl is covalent.
Wait wait. I'm very sure it's Al/Be...but not sure for HH is the only correct answerlost my one mark
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no almunium reacts in water AlCl3 reacts so does Be like a simple covalent chloride to form a complex how can some thing dissolve to form a complex?Wait wait. I'm very sure it's Al/Be...but not sure for H
That is true. Therefore only Group IV elements can form pi bonds. Carbon for example has electron configuration of 1s2.2s2.2p2. The 2s2.2p2 orbital will hybridize into 1s.1p(x).1p
Wait wait. I'm very sure it's Al/Be...but not sure for H
We still have MCQ and Practical to go. That's why I'm discussing(not arguing). The free ions of Al & Be chlorides conduct electricitydont argue over chem the only subject i will never admitt defeat on xD
no almunium reacts in water AlCl3 reacts so does Be like a simple covalent chloride to form a complex how can some thing dissolve to form a complex?
It reacts/hydrolyse to from hydrated ions...but still ionsno almunium reacts in water AlCl3 reacts so does Be like a simple covalent chloride to form a complex how can some thing dissolve to form a complex?
That is true. Therefore only Group IV elements can form pi bonds. Carbon for example has electron configuration of 1s2.2s2.2p2. The 2s2.2p2 orbital will hybridize into 1s.1p(x).1p.1p(z) or sp3. the p(z) hybridized orbital from two adjacent C atoms are parallel to each other. Hence form a pi bond. Can Oxygen undergoes the same hybridization?
partial hydrolysis man read partial hydrolysis . there are 50 percent of grade remaining hoping for excelent practical so i can relax for p1 xD
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