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gt wuld be 37
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ke is zeroDid we hav to show that the energy ie ke=o or just show that the speed is same ??
0.47 100% correctGuyz plz tell me the ans. Of q7 last part!!!
I dnt knw why many think that it was difficult
0.47 100% correct
I wrote 0.475( 3 sig. Fig.)0.47 100% correct
I shaded the whole graph........Dont think its right....guys which area we had to shade in q6 part 2
between time 20 and 26guys which area we had to shade in q6 part 2
around 8here are the answeres to what I got
Ans.1 coefficient of friction=0.8; a=2.55ms^-2
Ans.2 workdone against resistance=750J
Ans.3 tension in AP was 13 and in PB was 20
Ans.4 S=13m; v=5.66; S/2 and s at T/2 were both 3.25
Ans.5. P=20, v=3.33
Ans.6 attempted only parts i and ii which are simple left the third part blank
Ans.7 a=5.85; v=2.65; got the distance wrong I guess just calculated the distance of A after STRING BECAME SLACK: IT WAS 1.43
It would be really apreciable if you world spot my mistakes and tell me how many marks I will loose in q.7
and that how many marks can I get. Thanks in advance
Ans.5here are the answeres to what I got
Ans.1 coefficient of friction=0.8; a=2.55ms^-2
Ans.2 workdone against resistance=750J
Ans.3 tension in AP was 13 and in PB was 20
Ans.4 S=13m; v=5.66; S/2 and s at T/2 were both 3.25
Ans.5. P=20, v=3.33
Ans.6 attempted only parts i and ii which are simple left the third part blank
Ans.7 a=5.85; v=2.65; got the distance wrong I guess just calculated the distance of A after STRING BECAME SLACK: IT WAS 1.43
It would be really apreciable if you world spot my mistakes and tell me how many marks I will loose in q.7
and that how many marks can I get. Thanks in advance
i got o.48 which i rounded to o.5m in the last step0.47 100% correct
coefficient 25 / 30= 0.8Coficent of friction was 0.833????
Plz tell
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