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it was asking about distance covered in T/2 seconds in the 2nd part of question 4Speed is 2.6
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it was asking about distance covered in T/2 seconds in the 2nd part of question 4Speed is 2.6
no seriously i dont remember whether it asked for distance at T/2 or speed at T/2 .... can anyone cnfirm that ?6.5m
no seriously i dont remember whether it asked for distance at T/2 or speed at T/2 .... can anyone cnfirm that ?
They asked distanceno seriously i dont remember whether it asked for distance at T/2 or speed at T/2 .... can anyone cnfirm that ?
so how did you calculate it i just recalculated now and i still get 3.25 mThey asked distance
what was your broThey asked distance
it wasnt like thatt = s........therefore T/2=s/2......but yet use equation of motion and then get time.....replace t in v=u+at.....and u will be home
hey in frst part it also required the speed at S/2 rite????Question No.4
m g sin(θ) = m a ( cancel m at both sides )
g sin(θ) = a
a = 16/65 x 10
a = 2.46 ms^-2
V^2 = U^2 + 2 as
8^2 = O^2 + 2(2.46)(s)
S= 13m
Time taken to travel S
13 = 1/2 (2.46) T^2
T = 3.25s
T/2 = 1.63
S when T/2
1/2 (2.46)(1.63)^2
S = 3.25m
it wasnt like that
find time using v=u+at
acceleration is 10*sin@ = 10*16/65 = 2.46
8=0+ 2.46*T
T=3.252
T/2= 1.626
for finding distance apply s=ut + 0.5at^2
s=0(t) +0.5*2.46*1.626^2
s=3.25/
please correct me if i am wrong
as far as i remember it asked for the speed at S/2But I think the question was to calculate time when S was S/2.
I seriously can't remember what was the question
i
as far as i remember it asked for the speed at S/2
i dont think so i am also confused about the statement of the questionThis is exactly I'm doing right now.
But I think question was something else :/
same thing i took total distance as 117m and final time!!bro for c the initial time was 20 and the initial dist. was 92!
i did that way and got the correct ans!
hey i even don't remember what type of question was that and everything in the paper was easy except q6 and q711 so don't worry!!why is everyone asking about q4??nobodys helping me around q4 last part :'( :'(
i thinks that's what i got!!Question No.4
m g sin(θ) = m a ( cancel m at both sides )
g sin(θ) = a
a = 16/65 x 10
a = 2.46 ms^-2
V^2 = U^2 + 2 as
8^2 = O^2 + 2(2.46)(s)
S= 13m
Time taken to travel S
13 = 1/2 (2.46) T^2
T = 3.25s
T/2 = 1.63
S when T/2
1/2 (2.46)(1.63)^2
S = 3.25m
brother do you remember the question statement?i thinks that's what i got!!
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