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How was Mechanics Paper 42!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

How was the paper

  • Easy

    Votes: 27 19.0%
  • Hard

    Votes: 40 28.2%
  • Not Hard and Not easy

    Votes: 75 52.8%

  • Total voters
    142
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t = s........therefore T/2=s/2......but yet use equation of motion and then get time.....replace t in v=u+at.....and u will be home
 
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t = s........therefore T/2=s/2......but yet use equation of motion and then get time.....replace t in v=u+at.....and u will be home
it wasnt like that
find time using v=u+at
acceleration is 10*sin@ = 10*16/65 = 2.46
8=0+ 2.46*T
T=3.252
T/2= 1.626
for finding distance apply s=ut + 0.5at^2
s=0(t) +0.5*2.46*1.626^2
s=3.25/
please correct me if i am wrong
 
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But I think the question was to calculate time when S was S/2.

I seriously can't remember what was the question
 
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Question No.4

m g sin(θ) = m a ( cancel m at both sides )
g sin(θ) = a

a = 16/65 x 10
a = 2.46 ms^-2


V^2 = U^2 + 2 as
8^2 = O^2 + 2(2.46)(s)
S= 13m

Time taken to travel S
13 = 1/2 (2.46) T^2

T = 3.25s


T/2 = 1.63


S when T/2

1/2 (2.46)(1.63)^2
S = 3.25m
hey in frst part it also required the speed at S/2 rite????
 
Messages
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it wasnt like that
find time using v=u+at
acceleration is 10*sin@ = 10*16/65 = 2.46
8=0+ 2.46*T
T=3.252
T/2= 1.626
for finding distance apply s=ut + 0.5at^2
s=0(t) +0.5*2.46*1.626^2
s=3.25/
please correct me if i am wrong

This is exactly I'm doing right now.
But I think question was something else :/
 
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Question No.4

m g sin(θ) = m a ( cancel m at both sides )
g sin(θ) = a

a = 16/65 x 10
a = 2.46 ms^-2


V^2 = U^2 + 2 as
8^2 = O^2 + 2(2.46)(s)
S= 13m

Time taken to travel S
13 = 1/2 (2.46) T^2

T = 3.25s


T/2 = 1.63


S when T/2

1/2 (2.46)(1.63)^2
S = 3.25m
i thinks that's what i got!!
 
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