HOW WAS PHYSICS PAPER 2 AS!!!!!!!!!!!

[WhereAmazingHappens]

You are wrong, my friend. Using lambda/2 gave the answer as 1000 Hz. I am certain of that.

Sorry bro lambda/2 gives 500.

I did lambda/2 and got 500 and so did, it seems, everyone else.
Maybe you did an error in calculation

 

[mhalvi]

Sorry bro lambda/2 gives 500.

I did lambda/2 and got 500 and so did, it seems, everyone else.
Maybe you did an error in calculation

u r ryt it had to be multiplied by 2 but was .24x2 =.48

 

[Hertz]

are u sure its 500?? the frequency i mean

yes.. for sure. i tried it at home. and 80%of my class got it. (n my class is really smart). means i got NODES and ANTINODES QUESTION WRONG. coz it was intensity distance graph not amplitude distance graph

 

[Hertz]

wait wat??
lambda is 0.34m v=340 how can it b 500??

i remember one of the question ask what is the wavelength
neway, what u guys got for the Tension T??

something like 1567 or 1576 some thing like that for T

 

[Mattman]

how many marks was the question??

 

[confused123]

i dunno if they r rite
but i got 13m/s for the speed dunt remember the rest

yup 13.

 

[confused123]

something like 1567 or 1576 some thing like that for T

same answer.

 

[Doggybros]

I think i'm gonna get more than 50 this paper was ridiculously easy guys!
My previous post about tension was kinda related to this paper lol.
The graph was simple too!

 

[Doggybros]

threshold would be below 40, becoz evry1 i knw had dne fullishly, n paper was too long yarrr

It wasn't too long, you were just too slow

 

[furqan shah]

paper was average . not too good not too bad

 

[WhereAmazingHappens]

u r ryt it had to be multiplied by 2 but was .24x2 =.48

ya something like that i cant remember

 

[WhereAmazingHappens]

guys for the Young Modulus graph u have to draw, the gradient is twice the given graph right?

 

[Nisrit Pandey]

pretty sure it was 500. my class wrote 1000 too but wen i explained they agreed i was ryt

ye

You are wrong, my friend. Using lambda/2 gave the answer as 1000 Hz. I am certain of that.

ah agree with you the above guy is wrong

 

[Nisrit Pandey]

guys for the Young Modulus graph u have to draw, the gradient is twice the given graph right?

nope its not twice but lower it should touch the point (0.25,1.5)

 

[Ahmed Tariq]

For copper, Young Modulus is half. Hence, the force should be halved, i.e. 1.5 N.
Same graph but with peak at 1.5 N instead of 3.

 

[Mattman]

guys for the Young Modulus graph u have to draw, the gradient is twice the given graph right?

Eh? its half i think. E=Fl/Ae half the E means half of F

 

[WhereAmazingHappens]

nope its not twice but lower it should touch the point (0.25,1.5)

how can it be half??

 

[WhereAmazingHappens]

equation of young modulus (E)
E = (L)/m*A
L - length
m - gradient
A - area

so when you make m the subject of the formula

m = (L)/E*A
so when E is halved, m is doubled when L and A are constant

This is the correct way to do it

All of your'll thought when E is halved gradient is halved

 

[Ahmed Tariq]

The change in kinetic and gravitational potential energy, anyone?

 

[Ahmed Tariq]

equation of young modulus (E)
E = (L)/m*A
L - length
m - gradient
A - area

so when you make m the subject of the formula

m = (L)/E*A
so when E is halved, m is doubled when L and A are constant

This is the correct way to do it

All of your'll thought when E is halved gradient is halved

Young Modulus is (F/e)(L/A), where F/e was the gradient.