HOW WAS PHYSICS PAPER 2 AS!!!!!!!!!!!

[Nisrit Pandey]

Actually, it was a stationary wave, since it told you to label node and antinodes earlier. In a stationary wave, length b/w 3 nodes is wavelength, not 2. 0.34 cm was distance between 2 nodes, and half wavelength. Trust me, I made the same mistake initially. Wavelength was 68.5 cm, so 340/68.5x10-2 =496 Hz.

it was said an stationary wave can be formed! so label where the nodes and antinodes are! and i still remember my answer 0.34 was between 3 successive nodes i checked that thing while writing my answer

 

[ghazanferali16]

any idea about tomorrows 34?

 

[Mattman]

what were the axes btw

force against extension

how can a material with lower yg modulus require more force for the same extension?

 

[ghazanferali16]

WHat u guys awnsered for the last part of the paper? the mass conservation

it will be solved by e=mc square, part of the mass decrease, the mass defect is converted to energy.

 

[ghazanferali16]

force against extension

how can a material with lower yg modulus require more force for the same extension?

l and a were constant so F/e was equated to the gradient.

 

[hmlahori]

the paper was ok i actually finished it in time! couldnt believe that! but i messed up the potentiometer question for sure!

 

[Nisrit Pandey]

the paper was ok i actually finished it in time! couldnt believe that! but i messed up the potentiometer question for sure!

the potentiometer was a bit easier than what i expected!! what did you all get answer for the Values of C

 

[ghazanferali16]

the potentiometer was a bit easier than what i expected!! what did you all get answer for the Values of C

which question are you referring to?

 

[Sandhya Mahat]

what was Y? 1 or 2??

 

[Nisrit Pandey]

t

which question are you referring to?

he first question

 

[RAFFAY]

The paper was either TOO long for 1 hour or 1 hour is TOO short for the paper... :/
I cudnt draw the graph

HA HA HA....paper was easy but I made a huge blunder: I was doing paper considering time 1.15 minutes left 6 marks....LOL

 

[sagar187]

are u sure its 500?? the frequency i mean

Yeah..The nodes are situated at the bottom of the graph..Even I made the mistake..Its 500Hz

 

[gary221]

The paper was either TOO long for 1 hour or 1 hour is TOO short for the paper... :/
I cudnt draw the graph

Totally with u on tht!!
1 hr = defintely nt enough!!

 

[Mattman]

how many marks was the waves question??

What u all did for the KE/PE part

 

[Ali23]

ITS 1000Hz for sure.....people who r telin 500Hz made mistake in cm to m conversion.....ma whole class got 1000hz ...abt 56 students...LOL...still 500hz people thnk its wrng??lmao

 

[Nisrit Pandey]

my KE was 1. something and PE was 0.44 for ke it was simple just subtract two kinetic energies! for pe find the rebound height of the ball and use mgh

 

[Ahmed Tariq]

the potentiometer was a bit easier than what i expected!! what did you all get answer for the Values of C

The value of C was 1.04x10^-3 and the error was 9x10^-5.

 

[JD REBORN]

Exactly. So distance b/w 2 nodes i.e 0.34 cm, was half wavelength.

distance between two nodes is lamba/2=0.34 m

 

[Nisrit Pandey]

tha

The value of C was 1.04x10^-3 and the error was 9x10^-5.

thank god ahmed! you again have increased my confidence mine was the same oh yessssssssssssssssss

 

[JD REBORN]

ITS 1000Hz for sure.....people who r telin 500Hz made mistake in cm to m conversion.....ma whole class got 1000hz ...abt 56 students...LOL...still 500hz people thnk its wrng??lmao

Mr lamao distance between two nodes was 0.34 m and in a STATIONARY wave distance between two nodes is lambda/2=0.34 m.Now prove how i am wrong