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Post what you think that you will get for the M1 paper.
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what if a person get above 90?there is no A* in M1 , lol
out of range!! lol
can anyone remember what they got for 5c, i think it was find the time of the motorcycle from the first traffic light, to point A?i was talking from 100%
time was 70 seconds... how i did it was work put time for car to travel 990m i got 60 seconds for motorcycle its t for car+ 10 so 70 seconds and acceleration i got 0.4can anyone remember what they got for 5c, i think it was find the time of the motorcycle from the first traffic light, to point A?
would you be able to show your workings? because i too worked out the time for the car to travel 990m, but i got 92 seconds not 60 :/t time was 70 seconds... how i did it was work put time for car to travel 990m i got 60 seconds for motorcycle its t for car+ 10 so 70 seconds and acceleration i got 0.4
actually he said on the point of tilting so only RP or RQ hahaha :/ i may get 0 in this question and the speed time graph maan i did it all wrong except drawingmoments question was hard!!!! i left it blank only drew diagram and rp+rq = 50g+ mg so maybe 1/14 marks
can someone explain how they found the time of the motorcycle?? i worked out the time for the car and then added 10 seconds on.... i used u=0, v=22, s=990, and i worked out acceleration with v^2=u^2 + 2as, giving 22^2 = 2 x 990a, and a came out as 0.24, then i used v=u+at, and t came out as 92??? :/
ok sure will do... we know that that in the first 30 seconds the car traveled 330m.... 30x22/2(triangle)... after that it was at 22m/s for awhile so what i did was 990-330=660... now 660/22 = 30(square so dividing by speed gets time) seconds as well... we know that when the biker met with car speed of car was 22 so it hadnt decelerated upto then... so 30+30=60 now for biker it was 10 more seconds... 60+10= 70...can someone explain how they found the time of the motorcycle?? i worked out the time for the car and then added 10 seconds on.... i used u=0, v=22, s=990, and i worked out acceleration with v^2=u^2 + 2as, giving 22^2 = 2 x 990a, and a came out as 0.24, then i used v=u+at, and t came out as 92??? :/
ok thanks that makes sense :/ but i still dont understand why the way i did it is wrong :Lok sure will do... we know that that in the first 30 seconds the car traveled 330m.... 30x22/2(triangle)... after that it was at 22m/s for awhile so what i did was 990-330=660... now 660/22 = 30(square so dividing by speed gets time) seconds as well... we know that when the biker met with car speed of car was 22 so it hadnt decelerated upto then... so 30+30=60 now for biker it was 10 more seconds... 60+10= 70...
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