what concentrations did u use ?took 10 cm3 of hcl and added 40 water total 50,,,
50 kz my other volume was 50...
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what concentrations did u use ?took 10 cm3 of hcl and added 40 water total 50,,,
50 kz my other volume was 50...
hawwwwww u kidding me !, i did my q2 first becuz they r easy nd then u shud've done q1,,,,,but seriously, not to make u feel bad but woowww missed it ! unbelievableTym was short
Miss ho gayya graph
seriously :O.. majority found q1 difficult!Question 1 went good unlike question 2 :l
Umm, I wonder why an increasing curve is appropriate. It's wouldn't be scientifically rational to conclude that an exothermic reaction isn't exothermic for temperatures below 25*C. I think it was an overall decreasing curve (1) with a solubility of 1g/dm3 at 25*C (1) for a total of two marks. I'd like to know what you have to say because I could be wrong.I drew an increasing curve till 25 deg, then decreased it. That was the way it was supposed to be!
anamolous points were 10 and 6..... nt so sure if they wr correct though...How many marks will I lose if i get more than 2 anomalies?
Umm, I wonder why an increasing curve is appropriate. It's wouldn't be scientifically rational to conclude that an exothermic reaction isn't exothermic for temperatures below 25*C. I think it was an overall decreasing curve (1) with a solubility of 1g/dm3 at 25*C (1) for a total of two marks. I'd like to know what you have to say because I could be wrong.
Here's some solubility data to prove my thinking: http://en.wikipedia.org/wiki/Solubility_table
- the solubility of Ca(OH)2 decreases, & thus the Ksp decreases, with temperature
- The table lists the solubility in grams per 100 ml H2O
- 0.189 grams of Ca(OH)2 "dissolved/ 100 ml H2O" @ 0 Celsius
- 0.182 grams of Ca(OH)2 "dissolved/ 100 ml H2O" @ 10 Celsius
- 0.173 grams of Ca(OH)2 "dissolved/ 100 ml H2O" @ 20 Celsius
- 0.16 grams of Ca(OH)2 "dissolved/ 100 ml H2O" @ 30 Celsius
- 0.141 grams of Ca(OH)2 "dissolved/ 100 ml H2O" @ 40 Celsius
- 0.121 grams of Ca(OH)2 "dissolved/ 100 ml H2O" @ 60 Celsius
- 0.086 grams of Ca(OH)2 "dissolved/ 100 ml H2O" @ 80 Celsius
- 0.076 grams of Ca(OH)2 "dissolved/ 100 ml H2O" @ 90 Celsius
How many marks will I lose if i get more than 2 anomalies?
I think i managed to do question 1 well, but i really really messed up in Q2 with only 20 mins left, i only managed to get my table values, to make the axes for the graph and make a few points and joined them with a straight line, and my anomalous points were randomly chosen :/ I just said this and this would be anomalous and gave my reasons, which i guess maybe the reasons atleast will be considered? Wont they? And i wrote the correct formula for the salt BUT i didnt explain how i got there due to lack of time And i drew construction lines and wrote the formulae y2 - y1/x2 - x1 for the gradient....could anyone please help me out and see if ANY of what i wrote will secure me marks in Q2? Its the only one stressing me out Im hoping to get about 20ish atleast since thats where A*-A lies for P5. Im not looking for any direct answers since 24 hours isnt up, just like, if those general points gain marks. Thanks, whoever helps!
Well from what I've seen in the mark schemes this is how they break up the 3 marks.
Identify and circle the anomalous points (1)
Explain the deviation (too little precipitate, too much precipitate) and then give a reason from the procedure for the anomaly. (1)
The same description for the other point (1)
As for the construction line, you should get a mark but they probably won't give you a mark for the formula because for the second mark you had to deduce the actual values.
I forgot the marks for the very last part. If it had two marks you should get a mark for the correct formula. If it had 1 mark you probably won't.
Don't lose heart, I think the gt will be pretty low.
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