Lets Get Started (SAT Version)

[Thought blocker]

Three children guessed the number of jelly beans in a jar.The guesses were 98,137 and 164.None of the guesses was correct.One guess was off by 12,another by 27 and the third by 39.How many jelly beans were in the jar.

 

[Thought blocker]

For real numbers a, b, and c, ab = 1.5, bc = 6, and ac = 25. So abc=(A) 9
(B) 12
(C) 15
(D) 100
(E) 225

 

[Thought blocker]

If 2^x < 100 and x is an integer, how many of the 2^x + 2 integers will be divisible by 3 and by 2?

(a) 1

(b) 2

(c) 3

(d) 4

(d) 5

 

[Thought blocker]

What is the closest approximation of the solution of the equation 2x – 1 = 3x + 1?

(a) -4.42

(b) -5.81

(c) -3.22

(d) 4.93

(e) 3.33

 

[Thought blocker]

What is the range of (x – y) if 3 < x < 4 and -2 < y < -1?

(a) 4< x-y <5

(b) 1< x-y <3

(c) 1< x-y <5

(d) 4< x-y <6

(e) 3< x-y <6

 

[Thought blocker]

For some positive real number ‘a’, the first 3 terms of a geometric progression are a – 1, a + 3 and 3a + 1. What is the numerical value of the fourth term?

(a) 25

(b) 36

(c) 32

(d) 100

(e) 9

 

[MarcoReus]

A) n+20
125
C) 15
C) 3
C) -3.22
D) 4 < x-y < 6 (This one looks a little strange)

 

[Thought blocker]

A) n+20
125
C) 15
C) 3
C) -3.22
D) 4 < x-y < 6 (This one looks a little strange)

Nice try brother.
1) correct.
2) Incorrect.
3) correct.
4) correct.
5) Incorrect.
6) correct.
Well this were easy thought you will get all correct.

 

[MarcoReus]

How is the second one wrong?

98+27 = 125
137-12 = 125
164-39 = 125

Even in the 5th one, plugging in has C with the lowest difference between the answers.

 

[Thought blocker]

How is the second one wrong?

98+27 = 125
137-12 = 125
164-39 = 125

Even in the 5th one, plugging in has C with the lowest difference between the answers.

MY TYPING MISSTAKE
:/
1) Incorrect
2) correct

 

[MarcoReus]

How is 1 wrong?

Suppose n = 5

5 + 10 + 15 + 20 + 25 + 30 + 35 + 40 + 45 = 225
Mean = 225/9 = 25.

n = 5.
n + 20 = Mean
n + 20 = 25.

 

[Thought blocker]

The number of green and red tomatoes are 4n and 3n,

respectively, for some integer n. In this way, we can be

sure that the green-to-red ratio is 4n/3n = 4/3. We

need to solve the equation:

4n – 5 / 3n - 5 = 3/2

Cross-multiplying, 8n − 10 = 9n − 15 so that n = 5.

There were 3n, or 15, red tomatoes in the bag.

Working with the answers may be easier. If answer A

is correct, then there were 16 green tomatoes and 12

red tomatoes, in order to have the 4 to 3 ratio. But

removing five of each gives 11 green and 7 red, which is

not in the ratio of 3 to 2. If answer B is correct, then

there were 20 green tomatoes and 15 red tomatoes, since

20/15 = 4/3. Removing five of each gives 15 green and

10 red, and 15/10 = 3/2, so answer B is correct.


Get it .-.

 

[Awesome12]

How is 1 wrong?

Suppose n = 5

5 + 10 + 15 + 20 + 25 + 30 + 35 + 40 + 45 = 225
Mean = 225/9 = 25.

n = 5.
n + 20 = Mean
n + 20 = 25.

Yeah you are right.

 

[MarcoReus]

No. I have no idea what you just wrote there.

 

[Awesome12]

The number of green and red tomatoes are 4n and 3n,

respectively, for some integer n. In this way, we can be

sure that the green-to-red ratio is 4n/3n = 4/3. We

need to solve the equation:

4n – 5 / 3n - 5 = 3/2

Cross-multiplying, 8n − 10 = 9n − 15 so that n = 5.

There were 3n, or 15, red tomatoes in the bag.

Working with the answers may be easier. If answer A

is correct, then there were 16 green tomatoes and 12

red tomatoes, in order to have the 4 to 3 ratio. But

removing five of each gives 11 green and 7 red, which is

not in the ratio of 3 to 2. If answer B is correct, then

there were 20 green tomatoes and 15 red tomatoes, since

20/15 = 4/3. Removing five of each gives 15 green and

10 red, and 15/10 = 3/2, so answer B is correct.


Get it .-.

I don't think this is anyhow related to the first question

 

[Thought blocker]

I don't think this is anyhow related to the first question

Answer is B) n +180 not A!

 

[MarcoReus]

Dude? What have you even written there?

Suppose n is 20. If you keep going and adding (25, 30...) and then divide by 9, you reach a mean of 40. Which is n+20.
How can you even come with a mean of 200 there?

 

[Thought blocker]

http://www.erikthered.com/tutor/sat-math-hard-practice-quiz.pdf
Look pg : 9 and 10

 

[Awesome12]

The first term of a sequence is the number n, and each
term thereafter is 5 greater than the term before. Which
of the following is the average (arithmetic mean) of the
first nine terms of this sequence?
(A) n + 20
(B) n + 180
(C) 2n
(D) 2n + 40
(E) 9n + 180

Solve it using the sequences in A levels Maths

Sequence:

2, 7, 12, 17

n =2
d= 5

A.P progression


S9 = 9/2 [2a + (n-1)d]

S9 = 4.5 [4 +(8)(5)]

S9 = 198

198 / 9

=22


n + 20 = 22

 

[Awesome12]

Yeah and this is the explanation from the link you gave

1. A (Estimated Difficulty Level: 4)
The first nine terms of the sequence are:
n, n + 5, n + 10, n + 15, . . . , n + 40.
(You should probably write all nine terms out to avoid
mistakes.) Adding these terms up gives: 9n + 180. The
average is the sum (9n + 180) divided by the number of
terms (9). The average is then: (9n + 180)/9 = n + 20.