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how to find the maximum??????????In this case you have to find the x-coordinate by using this formula: -b/2a (( mines B "over" 2*A))
Then you will be able to find the y-coordinate -by the given formula- by substituting the value of X in the formela
Note: "A" is the first number in the formula beside the x^2 if no number the it's value is 1
And "B" is the 2nd number in the formula beside the x
Eg: x^2-6x+18=0
Then "A = 1" and "B = -6"
-in this example the grape don't touch the x-access- so the vertex of the minimum point is : -(-6)/2*1= 3
There for x=3 substitute it in the formula :
Y= (3^2)-6(3)+16
Y= 9
SO the coordinate is (3, 9)