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Mathematics: Post your doubts here!

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View attachment 38618 although i solved many questions of this type i dont know why my answers are not correct for this question.
View attachment 38619
(a)
Range = The Highest boundary of the Highest Class (in this case 5) - The Lowest boundary of lowest class (in this case 1) = 5-1 = 4
(b)
Median of a data with an 'odd' total frequency = [(total frequency+1)/2]th number = (125+1) = 63rd number = 2
(c)
mode is the number with highest freq. so it is, of course, 1.
 
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coz there r 2 pencils and out of these 2, either 1st will be green, or the 2nd one will be green.
there are two chances
1:
1st one is green
P(1st green) = (4/9) * (5/8) = 20/72
2:
2nd one is green
P(2nd green) = (5/9) * (4/8) = 20/72

so having the two mutually exclusive events (events which can NOT occur at the same time) we add the 2 probabilities.
P(only 1 is green) = (20/72) + (20/72) = 2(20/72)
got it?
if no, then try making a tree diagram, that'll make u understand it way better In Shaa Allah :)
and if u dont understand it then, then i cant do anything else :p
 
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coz there r 2 pencils and out of these 2, either 1st will be green, or the 2nd one will be green.
there are two chances
1:
1st one is green
P(1st green) = (4/9) * (5/8) = 20/72
2:
2nd one is green
P(2nd green) = (5/9) * (4/8) = 20/72

so having the two mutually exclusive events (events which can NOT occur at the same time) we add the 2 probabilities.
P(only 1 is green) = (20/72) + (20/72) = 2(20/72)
got it?
if no, then try making a tree diagram, that'll make u understand it way better In Shaa Allah :)
and if u dont understand it then, then i cant do anything else :p
yes i got it. thank you :)
 
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