- Messages
- 169
- Reaction score
- 117
- Points
- 38
View attachment 38756
180 + ACD + ACB = bearing of B from C
as we know BAC = ACD
so 180 + ACD + ACB = 180 + BAC + ACB
150 + ACB + BAC = 180
ACB + BAC = 30 = ACD + ACB
180 + ACD + ACB = 180 + 30 = 210
as we know BAC = ACD
so 180 + ACD + ACB = 180 + BAC + ACB the logic behind this ?
the bearing is 180 + the exterior and interior angles...i understand this part
but how is 180 also added to two interior angles of a trinngle
if we consider the sum of interior angles of trianle which sum to 180 then .. 180-150=30 which includes two angles that are left right ?