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Mathematics: Post your doubts here!

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how can i find the coordinates of a point by drawing a tangent. the gradient is 3 ?
past paper: 2012 paper 43 question 7(e)
just draw a tangent with that gradient of 3 and write down the coordinates where they intersect.
or perhaps, when u draw the tangent derive its equation and join the 2 eq.s (of that curve and of tangent)
 
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View attachment 38561 how do we know its in 5/11/7 order inside the circles? View attachment 38562
as 2 students study neither, so we are left with 25 - 2 = 23 students who study either of them.

then we know 16 students study french and 18 study Spanish.
and 16 + 18 = 34, whereas we have only 23 students who study.
so what do we take out the 'overlapping' number of students, and we do it this way.
34 - 23 = 11, so eleven students study both. we'll put these students in the intersection of french and spanish studying students.

as we are told, 16 students study french (including the students which study both, i.e. a total of eleven students)
so the students which study ONLY french = 16 - 11 = 5

the same way we subtract 11 from 18 to get
7 students which study only spanish.

i hope you got it :)
 
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how? would you please solve it


can you solve the second part (ii)
of histogram too

Well I figured out how to get the values but I don't understand how it makes sense, I'm guessing since there's 4 class width's. So basically you divide the frequency by difference in each of those time ranges. For example the first height.

Frequency = 5
Time taken = 60-40 = 20

5/20 * 4 = 1 , repeat with the other heights. That's how I got to the answers but I'd like someone to make sense of what I've said.
 
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upload_2014-4-8_18-14-9.pngi am getting the interquartile range as 100.5th student which comes about 72....anyone can help ?
 

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it just this that the 2 discs which we choose, the numbers on them should add upto 5.
e.g. 3 + 2 = 5
3 + 2 = 5
4 + 1 = 5
yes but its asking about the probability and if you consider it as you have said so its going to be 3/x

but thank you i just read the question again and i found it !
its 1 2 2 3 4 ....
there are total of 20 possible asnwers if you pair each number with the other 4
and if you do that each time consedering each number independantly (like pair (1,2) and (2,1) are considered different from each toher) so you end up with 6 possible solutions where the pairs add up to 5. ...so the answer is 6/20
i hope there is a shorter way to this ...but its for 3 marks!!
 
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interquartile range = Q3 - Q1
where
Q1 (lower quartile) = 25% of total freq.
Q3 (upper quartile) = 75% of total freq.

just subtract corresponding values of Q3 and Q1. it'll be ur interquartile range. got it?
i now th quation but its not matching with the answer. can you solve it please!
the answer is 8 :oops: in ms
 
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yes but its asking about the probability and if you consider it as you have said so its going to be 3/x

but thank you i just read the question again and i found it !
its 1 2 2 3 4 ....
there are total of 20 possible asnwers if you pair each number with the other 4
and if you do that each time consedering each number independantly (like pair (1,2) and (2,1) are considered different from each toher) so you end up with 6 possible solutions where the pairs add up to 5. ...so the answer is 6/20
i hope there is a shorter way to this ...but its for 3 marks!!
as there are two disc numbered 2. so there are 2 possibilities of getting 3 + 2
and the probability for getting a 2 and a 3 = (1/5) * (2/4)
prob. for getting a 4 and a 1 = (1/5) * (1/4)

so probability for getting 5 as the sum of two numbers = (1/5) * (2/4) + (1/5) * (2/4) + (1/5) * (1/4)

if my answer is not correct then u should solve it by drawing a tree diagram.
 
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i now th quation but its not matching with the answer. can you solve it please!
the answer is 8 :oops: in ms
Q3 = 75% of 200 = 150 ----------> 76 on the x axis
Q2 = 25% of 200 = 50 -----------> 68 on x axis

interquartile range = Q3 - Q1 = 76 - 68 = 8

got it?

and just for ur information, we call Q2 as 'median, coz its 50% of the total freq.
upload_2014-4-8_18-14-33.png
 
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Q3 = 75% of 200 = 150 ----------> 76 on the x axis
Q2 = 25% of 200 = 50 -----------> 68 on x axis

interquartile range = Q3 - Q1 = 76 - 68 = 8

got it?

and just for ur information, we call Q2 as 'median, coz its 50% of the total freq.
View attachment 38611
thank you so much. btw how did you use that marker on adobe acrobat reader, i am struggling in finding that tool its very useful in reading graphs ? :$
 
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