Mathematics: Post your doubts here!

[Phoenix Blood]

http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/ it's w05 q08 I want to know why it's 1/2a-1/2c and not 1/2aplus 1/2c and need explanation for 11

HAHAHA

 

[Phoenix Blood]

http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/ it's w05 q08 I want to know why it's 1/2a-1/2c and not 1/2aplus 1/2c and need explanation for 11

Minus because MA = AO + OM and since OA = a, AO=-a

 

[Shada Mohammed]

Minus because MA = AO + OM and since OA = a, AO=-a

But the answer was 1/2a --1/2c

 

[Phoenix Blood]

http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/ it's w05 q08 I want to know why it's 1/2a-1/2c and not 1/2aplus 1/2c and need explanation for 11

Find the perimeter of the table. Exclude the inner part.
Since there are four sides of the rectangle that make the table's perimeter, you multiply it by 4.
So 4*4=16m
We know that 4 quarters make a compete circle, so we can just simply find the circumference of one circle using radius 1.2m, and the formula 2πr.
So, 2πr, 2*π*1.2 = 7.54m

Now add these.
7.54+16
=23.54 m
This is the table's perimeter.

Since each person occupies 1m around the table, we can allow 23 people to sit.
We ignore the decimal because no one can squeeze into the remaining 0.54m.



The sides crossed red make the perimeter.

 

[Phoenix Blood]

But the answer was 1/2a --1/2c

OM = 1/2c + 1/2a
MA = -a + 1/2c + 1/2a
MA = 1/2c - 1/2a

 

[Shada Mohammed]

Find the perimeter of the table. Exclude the inner part.
Since there are four sides of the rectangle that make the table's perimeter, you multiply it by 4.
So 4*4=16m
We know that 4 quarters make a compete circle, so we can just simply find the circumference of one circle using radius 1.2m, and the formula 2πr.
So, 2πr, 2*π*1.2 = 7.54m

Now add these.
7.54+16
=23.54 m
This is the table's perimeter.

Since each person occupies 1m around the table, we can allow 23 people to sit.
We ignore the decimal because no one can squeeze into the remaining 0.54m.

View attachment 48122

The sides crossed red make the perimeter.

You are simply amazing thanks

 

[Phoenix Blood]

You are simply amazing thanks

UW :')

 

[idklol]

Um... was this in the IGCSE?

Not that I've ever seen, hope not!

 

[Kushal lodha 5336]

guys i have a doubt in may/june 2013 paper 23 ques 19 b(ii) (0580) and can someone give me a link about postion vectors because i srsly need help

IGCSE is over, concentrate on your AS level bro..

 

[Phoenix Blood]

IGCSE is over, concentrate on your AS level bro..

Maybe it isn't over for him.

 

[Kushal lodha 5336]

Maybe it isn't over for him.

Haha, lol!
But he is the topper...!!
He had got an A* in his IGCSE Mathematics..!

 

[Phoenix Blood]

Haha, lol!
But he is the topper...!!
He had got an A* in his IGCSE Mathematics..!

Cool.

 

[Shada Mohammed]

Q The perimeter of an equilateral triangle is 85cm, to the nearest cm
complete
Limits of its perimeter that I worked it out are 84.5cm and 85.5cm
The other part of the question asks me to get the limits of length of one side the limits were 28.2cm and 28.5cm. Why the limits aren't 27.8cm and 28.8 cm

 

[Shada Mohammed]

S=ut+1/2at^2 make a subject

 

[Phoenix Blood]

Q The perimeter of an equilateral triangle is 85cm, to the nearest cm
complete
Limits of its perimeter that I worked it out are 84.5cm and 85.5cm
The other part of the question asks me to get the limits of length of one side the limits were 28.2cm and 28.5cm. Why the limits aren't 27.8cm and 28.8 cm

Divide 84.5 by 3, you get 28.167 = 28.2 cm
Divide 85.5 by 3, you get 28.500 = 28.5 cm

How are you getting 28.7 and 28.8?

 

[Phoenix Blood]

S=ut+1/2at^2 make a subject

S=ut+1/2at^2
S - ut = 1/2at^2
(S - ut) / (1/2t^2) = a

Or is it this? :

S=ut+1/2at^2
S - ut = 1/2at^2
S - ut / 1/2 = at^2
(S - ut / 1/2 ) / t^2 = a

 

[tafadzwa]

AsSalamoAlaikum Wr Wb...

Stuck somewhere in Maths?? Post your queries here! Members around will help you InshaAllah.

NOTE: If you have any doubt in the pastpper questions, then kindly post the link to the paper!

May Allah give us all success in this world as well as the HereAfter...Aameen!!

SEQUENCES-Points to remember:
Many people find it hard, but to be honest it's just more of logic..that's all!

Sequences!

Using log for indices.

please help me with this question in complex numbers
For complex numbers satisfying |z-(1+u)| = 1, find the greatest possible value of |z|. thankkk uuu

 

[Phoenix Blood]

please help me with this question in complex numbers
For complex numbers satisfying |z-(1+u)| = 1, find the greatest possible value of |z|. thankkk uuu

Is this an IG question?

 

[tafadzwa]

Is this an IG question?

noo its A level

 

[Phoenix Blood]

noo its A level

Then post it in the A Level Math doubts forum
People will try help you out there.