Mathematics: Post your doubts here!

[hredoymohammad]

Its rotation 180 degrees and the centre will be the mid-point of the line RS. It won't be on a graph.

n wat about dis?

 

[Iridescent]

n wat about dis?

bout what?

 

[CaptainDanger]

http://www.xtremepapers.com/CIE/Cambridge O Levels/4024 - Mathematics/4024_w10_qp_22.pdf ...can anyone help me with no 10(iv) a...i have done upto (a b) (0 1 0) = (0 2 0) but den wat?? i can find it out if it was 2 * 2 matrix...but how to deal with
c d ... 0 0 1 .... 0 0 3.......................................................................................................................
2*3 matrix n in iv(b) y it is not enlargement??? n how do we know if its enlargement or stretch?

Q10 b) iv) a
All the transformation matrices are 2 into 2...
To find the matrix
Image Matrix = Transformation Matrix into Original Matrix
Put the values, solve the right side of the equation and then compare the a b c d values to the left side to find them out...

)b
The matrix you have found out in A gives the information that it is STRETCH... In enlargement the scale factor is same... Here we get two different scale factors... 2 and 3...

 

[Iridescent]

http://www.xtremepapers.com/CIE/Cambridge O Levels/4024 - Mathematics/4024_w10_qp_22.pdf ...can anyone help me with no 10(iv) a...i have done upto (a b) (0 1 0) = (0 2 0) but den wat?? i can find it out if it was 2 * 2 matrix...but how to deal with
c d ... 0 0 1 .... 0 0 3.......................................................................................................................
2*3 matrix n in iv(b) y it is not enlargement??? n how do we know if its enlargement or stretch?

The matrix is:
(2 0)
(o 3)
Its not enlargement cz the point (0,0) remains unmoved. In its enlargement, we need a centre of enlargement which would move that point too. I guess. Plz correct me if i am wrong.

The transformation is: stretch 2 units on x axis n 3 units on y axis.

 

[rawia ahmed]

hyyyyyyyyyy ppl i really need help abt how can i get a really old papers of math :/

 

[svenas]

any body help in this question plz:
Bag A contains 3 red balls and 3 blue balls.
Bag B contains 1 red ball and 3 blue balls.
A ball is taken at random form bag A and placed in bag B . A ball is then chosen from bag B. What is the probability that the ball taken from B is red??​

 

[ktc]

any body help in this question plz:​

Bag A contains 3 red balls and 3 blue balls.​

Bag B contains 1 red ball and 3 blue balls.​

A ball is taken at random form bag A and placed in bag B . A ball is then chosen from bag B. What is the probability that the ball taken from B is red??​

Could you provide the link to this question [paper], please?

 

[svenas]

Could you provide the link to this question [paper], please?

No, it's from my text book

 

[hredoymohammad]

http://www.xtremepapers.me/CIE/Cambridge IGCSE/0580 - Mathematics/0580_s08_qp_2.pdf question 10...i m not getting it..one has solved it here http://www.xtremepapers.com/community/threads/maths-paper-2-2008-help.5422/#post-66879 but when pie r2 h where did he get 4 as radius?? it is no where mentioned in the question?

 

[Iridescent]

Q: In a street of 150 houses, three different newspapers are delivered: T, G and M. Of these, 40 receive T,35 receive G and 60 receive M; 7 receive T and G, 10 receive G and M and 4 receive T and M; 34 receive no paper at all. How many receive all three?
Note: If '7 receive T and G', this information does not mean 7 receive T and G only.


Plz do mention the equation!
Thanx

 

[ktc]

http://www.xtremepapers.me/CIE/Cambridge IGCSE/0580 - Mathematics/0580_s08_qp_2.pdf question 10...i m not getting it..one has solved it here http://www.xtremepapers.com/community/threads/maths-paper-2-2008-help.5422/#post-66879but when pie r2 h where did he get 4 as radius?? it is no where mentioned in the question?

The equation for the volume of a cylinder = πr^2h

Volume of the cylindrical glass:

= π (4^2) (6) = 301.59 cm3

It’s given the glass can be filled with water from the cylindrical jar 216 times.

Therefore, the volume of the jar = 301.59 x 216

= 65144.1 cm3

Both the cylinders are symmetrical, so to calculate the radius of the jar:

Let’s say, the radius of the jar = r

301.59/65144.1 = 4^3/r^3

r^3 =[64 x 65144.1]/301.59]

r = 24 cm.

To calculate the height of the jar:

πr^2h = 65144.1 cm3

π (24^2) h = 65144.1 cm3

h = 65144.1/ [π (24^2)]

h = 36 cm.

Q: In a street of 150 houses, three different newspapers are delivered: T, G and M. Of these, 40 receive T,35 receive G and 60 receive M; 7 receive T and G, 10 receive G and M and 4 receive T and M; 34 receive no paper at all. How many receive all three?
Note: If '7 receive T and G', this information does not mean 7 receive T and G only.


Plz do mention the equation!
Thanx

Draw a Venn diagram. It makes the question sound a whole lot easier that way.

Let’s say, n(TGM) = x

The equation used when it comes to 3 sets being involved is:

n(T)+n(G)+n(M) - {(nTG)+n(GM)+n(TM} +n(TGM) = 150 - n(T'G'M')

= 40 + 35 + 60 – [7 + 10 + 4 + x) = 150 – 34

= 114 + x = 116

x = 116 – 114

x = 2

Hence, 2 houses receive all three.

 

[Iridescent]

Q: A(2,3) B(5,8)
Find the coordinates of the points equidistant from x-axis and y-axis.

 

[GetSomeLife]

Q: A(2,3) B(5,8)
Find the coordinates of the points equidistant from x-axis and y-axis.

I think A and B has nothing to do with it...
You just have to form a line y=x

 

[smzimran]

Q: A(2,3) B(5,8)
Find the coordinates of the points equidistant from x-axis and y-axis.

Coordinates of points which are on AB and are equidistant from x and y axis?

 

[Iridescent]

Coordinates of points which are on AB and are equidistant from x and y axis?

Yes

 

[GetSomeLife]

Yes

So put it THAT way!

 

[Iridescent]

The question is based on A and B. But i dont find any such point. Can it be even be (0,0).
The equation of the line is y=(5/3x) -1

 

[smzimran]

The question is based on A and B. But i dont find any such point. Can it be even be (0,0).
The equation of the line is y=(5/3x) -1

A(2,3), B(5,8)
Find the equation of AB and solve it simultaneously with y = x.
Equation of AB:
m(AB) = (8-3)/(5-2)
m(AB) = 5/3
Equation --> y - 3 = (5/3) (x-2)
3y - 9 = 5x - 10
3y = 5x -1
Now solve this with y = x
to get the coordinate (0.5,0.5)

 

[Iridescent]

Okay i found it!
When x=y, the equation will be x=5/3x-1.
x+1=5/3x
3x+3=5x
5x-3x=3
2x=3
x=3/2
S0, y=3/2

 

[smzimran]

I got the point as (1.5,1.5) and it lies on the line.

No, it does not.
Lets check...
The equation of AB is:
3y = 5x - 1
Lets substitute (1.5,1.5) in this
3(1.5) = 5(1.5) -1
4.5 = 7.5 - 1
4.5 = 6.5
See, the equation is not satisfied.