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Mathematics: Post your doubts here!

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I spent 30 mints on this part, cudnt get it =\ !!
Question 6, (c)
pi x 1.5^2 = 7.1
141.3-15.7 =125.6
12 x pi x 9 =339.3
pi x 4.5 = 63.617
7.1 + 125.6 + 339.3 + 63.617 = 535.617
if you need more details just tell me :) .. hope u got it :)
 
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p4 question
oct4 questin 4dii,
Mj10 varient 41 questn 8dii
June06 questin 3cii,iii plz plz help me
oct7 questoN 3 all part kndly watinìng 4r ur reply
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may 2010 ---> you have to find the intersection point between the 2 curve to get the value of x ( there r 2 values x=2 and x=0.4 )
oct 2007 --->a-i) make substitution in the first equation with x=0 s0 it will be ( 0,1 )
ii)make substittion the first time with Y=0 and the second time with X=0 so the ans. is ( 0,4) (4,0)
b)since you have 2 points (0,4) and (4,0) work out the gradient
c) X<0
d)we said before that the intersection point is the points where the 2 equaions are equal so it will be ((x^2+1=4-x ))
e) use the quadratic formula to get the value of X (( 1.30 and -2.30 ))
f) (1.30 + -2.30)/2 = -0.5
hope i helped :)...got it ??
 
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for transformation matrix there is a particular way to find out....will be posting it in a few hours...till then just brush up your matrices please
 
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HERE YOU GO FOR TRANSFORMATIONS. ANY DOUBTS DO ASK. THERE ARE OTHER METHODS IF YOU FIND THIS ONE DIFFICULT. I'LL POST THOSE IF YOU WISH.
 

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HERE YOU GO FOR TRANSFORMATIONS. ANY DOUBTS DO ASK. THERE ARE OTHER METHODS IF YOU FIND THIS ONE DIFFICULT. I'LL POST THOSE IF YOU WISH.
what about if we have a triangle for example it won't be 2x2 matrix !!
should we take only 2 points ??
 
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what about if we have a triangle for example it won't be 2x2 matrix !!
should we take only 2 points ??
yeah you just take two point (object) and then the images corresponding points
try a few and see if u get the correct answer...otherwise ill give u a different method
 
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yeah you just take two point (object) and then the images corresponding points
try a few and see if u get the correct answer...otherwise ill give u a different method
yeaaaaaaaaah... i seem like didn't look at the lesson for years :D ....i will :) thanx alot
 
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GUYS MAJOR PROBLEM
I NEVER TOOK THIS THING ABOUT BEARINGS WHEN A SIDE IS EAST OF SOMETHING ! COULD ANYONE EXPLAIN IT TO ME :cry: PLEASE ???
 
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Can anyone explain to me this probability question in O/N 09 Paper 42:
http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w09_qp_4.pdf
I didn't understand question 3 c
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we have 2 cards with no. 1
the probability of it is 2/6 the we solve bii) the first not 1 is 4/6 and the second is 1 is 2/5 ((without replacement)) so the probability that one card is 1 from 2 cards is 4/6 x 2/5
then he wants that 1 card chosed is 1 before the third try ---so we have the probability that 1 from 2 cards has the no.1 . add this to the probability of getting 1 which is 2/6-------->2/6+ 4/6 x 2/5 = 3/5
 
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