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Mathematics: Post your doubts here!

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Thanks always smile.

I have some other doubt. How to answer question 6 b) iii:
http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w09_qp_4.pdf
no need :)
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when you solved the equation f(x)=g(x) you get the intersection point then make those 2 values in an inequality so that x is between them 2
((( -4.5<x<1.4 ))) ---> check it ( in the area between the 2 values g(x) is greater than f(x)
the intersection points are the limits of the relation between the 2 equation
hope u got it :)
 
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no need :)
------
when you solved the equation f(x)=g(x) you get the intersection point then make those 2 values in an inequality so that x is between them 2
((( -4.5<x<1.4 ))) ---> check it ( in the area between the 2 values g(x) is greater than f(x)
the intersection points are the limits of the relation between the 2 equation
hope u got it :)
Yes, I got it. Thanks.
 
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soo my calculator went crazy 2 or what :confused:
A calculator doesn't ever make a mistake. There is a trick to use the cosine rule using a calculator:

To find a side we use this method:
The formula which you need is a2= b2+c2-2bc x cos A
In your calculator do it part by part.

Like first b2+ c2.
Then do - (2 x b x c x cos A)
Then at last do a square root to the answer you got.

The trick is just to do it part by part.
 
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A calculator doesn't ever make a mistake. There is a trick to use the cosine rule using a calculator:

To find a side we use this method:
The formula which you need is a2= b2+c2-2bc x cos A
In your calculator do it part by part.

Like first b2+ c2.
Then do - (2 x b x c x cos A)
Then at last do a square root to the answer you got.

The trick is just to do it part by part.
i do this but the same error happens ..... the answers ARE NOT THE SAMEEEE
 
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I answered this today! I forgot about that. See:
Let <DBA= y
x+3 can be considered as the opposite. So 4+3=7
And 2x+5 is the adjacent. So 2 x 4+ 5=13
Remember: We got x value before

Now, if you can notice Triangle DAB can be a right angled triangle. So use the tan rule.
1. tan y=opp/adj
2. tan y= 7/13
3. y= tan^-1 x (7/13)
4. You now get 28.3
 
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I answered this today! I forgot about that. See:
Let <DBA= y
x+3 can be considered as the opposite. So 4+3=7
And 2x+5 is the adjacent. So 2 x 4+ 5=13
Remember: We got x value before

Now, if you can notice Triangle DAB can be a right angled triangle. So use the tan rule.
1. tan y=opp/adj
2. tan y= 7/13
3. y= tan^-1 x (7/13)
4. You now get 28.3
NOOOO MY CALCULATOR GAVE ME 31.4 :mad:
 
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