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Mathematics: Post your doubts here!

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heeeeey calm down it's simple
make an equation from the dimensions he gave you :
(x+1)(x+2)/2=x^2
expand (x+1)(x+2) ----> x^2 + 2x+x+2 ---> x^2+3x+2
then make cross multiply ---> x^2+3x+2= 2x^2 ( -2x^2) ----> -x^2+3x+2=0 ( multiply - ) ---> x^2-3x-2=0
oh sorry i meant 9 A part IV :p
 
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?? its october november 10 varient 41 questions 9 part A IV :p?
i think i got it :p
look at the pattern of the first seq.( 1,2,3,....) and the pattern given in the question which is ( 3,6,9,...) .... you will find that the difference between them that the first seq. x3 gives the second one ... SO ..... ---> P50 = 1275 (in the first seq) BUT IN THE SECOND ---> P50= 1275x3 = 3825
hope u got it :)
 
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i think i got it :p
look at the pattern of the first seq.( 1,2,3,....) and the pattern given in the question which is ( 3,6,9,...) .... you will find that the difference between them that the first seq. x3 gives the second one ... SO ..... ---> P50 = 1275 (in the first seq) BUT IN THE SECOND ---> P50= 1275x3 = 3825
hope u got it :)
ya i got but p6 is 1 3 6 10 15 :S ?
 
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694
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i think i got it :p
look at the pattern of the first seq.( 1,2,3,....) and the pattern given in the question which is ( 3,6,9,...) .... you will find that the difference between them that the first seq. x3 gives the second one ... SO ..... ---> P50 = 1275 (in the first seq) BUT IN THE SECOND ---> P50= 1275x3 = 3825
hope u got it :)
and in first sequence its 1 2 3 4 but the other one begins from 15 :S
 
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