Mathematics: Post your doubts here!

[diamondsky]

so total surface area is simply the total summation of he areas, it doesn't have a definite formula right?
and for question 6(e), i checked the answer and the only way to find the distance of the line CE is by using Pythagoras theorem. however, i'm wondering why Pythagoras theorem has been used because the angle CBE is not at 90 degrees, from the angle at which we are viewing the prism
THANKS BY THE WAY

6.d) angle CAE is 90 so u can find AE and den CE
der is a formula for surface area :
cube = 6 x sides^2
cuboid = 2(lb + bh +lh)
cylinder = 2(pi)rh
cone = (pi)rl
sphere = 4(pi) r^2
bt not fr such irregular figures

 

[Fatima18]

yeah, your right it's time consuming, that's why I'm looking for notes. maybe they can have faster and easier techniques of solving sequences in a shorter period of time

Yeah, so are there any formulas for sequences?

 

[Igcse stuff]

6.d) angle CAE is 90 so u can find AE and den CE
der is a formula for surface area :
cube = 6 x sides^2
cuboid = 2(lb + bh +lh)
cylinder = 2(pi)rh
cone = (pi)rl
sphere = 4(pi) r^2
bt not fr such irregular figures

thanks a lot that really helped

 

[Igcse stuff]

Yeah, so are there any formulas for sequences?

the formula i found is

a+(n-1)d, a=first term in a sequence, n=number of terms e.g 5th term in a sequence, d= the difference in between the terms which should be the same through out the sequence.

however, my teacher told me this is for a-level. so i don't think it can be that useful in the exams but it helps when your trying to find the solution to a problem.

 

[Igcse stuff]

Can someone please help me by explaining step by step how to do these questions from 0580 may/june 2012 paper 21?
Questions 17, 15b and 20.
Thanks!

can you upload paper 4 of the same may/jun variant you've uploaded?

 

[Kieran]

can you upload paper 4 of the same may/jun variant you've uploaded?

Here you go...

 

[Igcse stuff]

Here you go...

thanks a lot, check out our variant

 

[Kieran]

thanks a lot, check out our variant

Thanks. I think i might be variant 3

 

[Igcse stuff]

Thanks. I think i might be variant 3

your welcome.

 

[Igcse stuff]

does anyone have notes on sets? please help

 

[diamondsky]

the formula i found is

a+(n-1)d, a=first term in a sequence, n=number of terms e.g 5th term in a sequence, d= the difference in between the terms which should be the same through out the sequence.

however, my teacher told me this is for a-level. so i don't think it can be that useful in the exams but it helps when your trying to find the solution to a problem.

dis formula works bt d prob is dat it will only work wen diff btween 2 terms is constant throughout
eg. 1,4,7,10 - it works
1,4,9,16,25 - it doesnt work

 

[Fatima18]

the formula i found is

a+(n-1)d, a=first term in a sequence, n=number of terms e.g 5th term in a sequence, d= the difference in between the terms which should be the same through out the sequence.

however, my teacher told me this is for a-level. so i don't think it can be that useful in the exams but it helps when your trying to find the solution to a problem.

Thank you!

 

[Fatima18]

dis formula works bt d prob is dat it will only work wen diff btween 2 terms is constant throughout
eg. 1,4,7,10 - it works
1,4,9,16,25 - it doesnt work

Well then, do you know the other formulas of sequences?

 

[diamondsky]

nope

 

[Igcse stuff]

Thank you!

your welcome

 

[Igcse stuff]

who's planning to do a-levels or ib?
and which of the two is better off doing?

 

[dogcatgone]

so who's doing paper 43? for maths igcse? i need some notes

 

[AAnsarii]

54+21+8a+45/ 17+a=7.2 (mean = sigma fx/sigma f)
120+8a=7.2(17+a)
120+8a= 122.4+7.2a
2.4=0.8a
a= 2.4/0.8= 3

Thanks bro
n u appearing 4 ig's? all d best...gave mine last term...

 

[AAnsarii]

who's planning to do a-levels or ib?
and which of the two is better off doing?

a levels is easier than ib

 

[AAnsarii]

Is the ans. 3.00

tx 4 d ans... (advice, dnt tk 2 ur heart) wud b nice if ud xplain, sp others
ask me y???

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ive already done ig maths alhamdulillah​