Mathematics: Post your doubts here!

[Fatum Zuh]

WOW ur Questions are soo long....... for this one .... just form equations and replace them in different equations its very easy but concentrate!

from where did you get 2y in '-x+2y=18'

 

[Rania1]

but i perfectly got what u said ! i do it this way too but that one is easier and looks more sophisticated,,

Looks like you understand more than i do

 

[manya]

from where did you get 2y in '-x+2y=18'

y+z=18
and z=x+y
so place x+y instead of z
x+y+y=18
x+2y=18
and sorry there is no -with x

 

[Fatum Zuh]

I need help PLEASE
http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w12_qp_41.pdf
Question 1(d)(ii) Can you show me the steps? I have Maths paper 4 tomorrow so please anyone ans quickly. Thnks

 

[Fatum Zuh]

y+z=18
and z=x+y
so place x+y instead of z
x+y+y=18
x+2y=18
and sorry there is no -with x

thank you
can you answer my other question pls?
I need help PLEASE
http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w12_qp_41.pdf
Question d(ii) Can you show me the steps? I have Maths paper 4 tomorrow so please anyone ans quickly. Thnks

 

[manya]

i

I need help PLEASE
http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w12_qp_41.pdf
Question 1(d)(ii) Can you show me the steps? I have Maths paper 4 tomorrow so please anyone ans quickly. Thnks

if u check in the previous pages iv posted a pic i guess after pg
167

 

[manya]

i

if u check in the previous pages iv posted a pic i guess after pg
167

sorry its page 167 only just check in the end

 

[manya]

sorry its page 167 only just check in the end

tell me if u found it or else ill post it again

 

[Rania1]

Question 7B
http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s08_qp_4.pdf

B) i) cyclic ii) since tc and bo are parallel, alt. interior angles are equal so x = 40 . OA and OB are both radii so AOB is an isosceles triangle. Both base angles are equal and so 130 + 2y = 180 , y = 25 . Angle Z is supplementary to x + y becuase they are on a cyclic quadrilateral so, 180 - 25 - 40 = z , z = 115.

iii) angle oct is equal to 90 because angle between radius and a tangent is always 90.

iv) angle Aoc = 2 x z because they are on the same segment so Aoc = 230.

 

[tiki-taka]

Guys when do we use (log)

 

[Fatum Zuh]

this is the answer of oct nov 2012 p2 q no 1 dii

Thank you very much
You really know how to make a person happy

 

[Fatum Zuh]

do any of you got notes to help me clear my doubts in probability?

 

[tiki-taka]

0580/43/O/n/11
Q-8e....can sum1 show the working

 

[shazmina]

2/5 x 1/4. thats easy

tnx u...

 

[Faaiz Haque]

http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s08_qp_4.pdf
Question 7 B

 

[Faaiz Haque]

B) i) cyclic ii) since tc and bo are parallel, alt. interior angles are equal so x = 40 . OA and OB are both radii so AOB is an isosceles triangle. Both base angles are equal and so 130 + 2y = 180 , y = 25 . Angle Z is supplementary to x + y becuase they are on a cyclic quadrilateral so, 180 - 25 - 40 = z , z = 115.

iii) angle oct is equal to 90 because angle between radius and a tangent is always 90.

iv) angle Aoc = 2 x z because they are on the same segment so Aoc = 230.

This is part A) I asked B) , thanks anyways

 

[Timi Adeg]

Can anyone help me solve the graph question in oct/nov 2011 paper 41. Question 5. Much appreciated

 

[ZaqZainab]

i made a really stupid mistae but i guess in sha Allah it will be above 64

I calculated mine and just had one mistake so i will lose only one mark

 

[manya]

I calculated mine and just had one mistake so i will lose only one mark

gr8

 

[ZaqZainab]

Guys when do we use (log)

used in indices
3^x=1/3
so log(3)/log(1/3)=x