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No i dont get the ans. 12/30+ 16/30 + 3/30 = 31/30
The ans is 5/6.
Oh sorry there has been formula mistake
it should 12/30 +16/30 - 3/30 since intersection has to be deducted as in formula of set
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No i dont get the ans. 12/30+ 16/30 + 3/30 = 31/30
The ans is 5/6.
By setting both equations equal, we get kx+6=x^2+3x+2k.http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_qp_11.pdf
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_ms_11.pdf
please explain question 9 part(ii) i don't get whats done in the marking scheme
Where are u stuck? Are you done with the first part?need help in P1 maths M/J 2009..
Q4??
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s09_qp_1.pdf
Plss helpp meeee.. thanks
By setting both equations equal, we get kx+6=x^2+3x+2k.
By refining the resultant equation, we get x^2 +(3-k)x +2k - 6 = 0
Set b^2-4ac = 0 and simplify.
Consequently, you get a quadratic in k. Solve it and you have the values for k.
i am stuck in the all of the questionWhere are u stuck? Are you done with the first part?
i)need help in P1 maths M/J 2009..
Q4??
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s09_qp_1.pdf
Plss helpp meeee.. thanks
thank you so much..but dude what do u mean by "a - 9 therefore 3=6"..didnt get thati)
'a' is the amplitude of the function.
a = 9 - 3 = 6
'b' is the number of cycles if in 2pi
The graph shows 2 cycles in 2pi and therefore b = 2
'c' is the y-intercept. Its the number of units the graph has shifted upwards.
c=3
ii) You got the values of a, b and c.
y = 6sin2x + 3
For y = 0,
6sin2x + 3 = 0
sin2x = -1/2
2x = 7pi/6
x = 7pi/12
We could've got another solution too but the question asks for the 'smallest' value of x and thats why we exclude the value from the 4th quadrant.
Its a bit difficult to explain it like that. If you could get a question from past-papers involving those concepts, I will be grateful.hey dug thanks a lot for the last post can u tell me any more basics for the past - paper questions on functions .. involving completed square forms n finding 'A' 1,1 functions , domains ranges of inverses , findhing range when x has a domain of real values n all etc etc... Would appreciate it a LOT
a = 9 - 3thank you so much..but dude what do u mean by "a - 9 therefore 3=6"..didnt get that
'Start' ?Yea but i want to start with the basics so :/
its ok..sorry if i am annoying u but is it 9-3 cuz it didnt start from 0?a = 9 - 3
a = 6
Sorry I mixed up the lines.
Exactly!! If it started from the origin, then 'a' would have been equal to 9. You could tell that just by looking at the graph.its ok..sorry if i am annoying u but is it 9-3 cuz it didnt start from 0?
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