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Mathematics: Post your doubts here!

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Need help for q. no 5 mechanics part 2? the coefficient of friction? tq o/n 02
 

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hmm You gotta resolve it down the plane and up the plane. You will get two equations 150sin 35 degree = X + F
2nd eq when the particle is moving up is 150sin 35 degree = 5X - F solve it simultaneously to get rid of x or f. add them u will get 300sin 35 = 6X , x = 28.7 N
now u have to calculate miyaaoun [ u = F/R ]calculate F by putting X value calculated earlier in any of those two equations then divide by R to get mu which is 57.36 / 123 = .47
 
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okay now that question above is out of my mind :shock:
Now good gracious!!! How can we solve this equation:
(2-y)^5
This mean u have to multiply it by five times!!! :shock: :O:
 
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woah woah..........easy easy dude...............so thats a big solution :good: ..............i think i am not studying this right now..............cz i have just started a levels.
 
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