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if u mean for part ii , then u just assume any value, I assumed it was 2
what should we do if Rsin(x-theeta) is the condition.How will we find the second answer in the range?assalamoalaikum wr wb!
alright...now u know the other angle would be 360 - 50.76 ...right? but that is out of the range given..now remember that in the fourth quadrant angle can either be 360 - x or alternatively be written as "-x "
so we have
(2x-71.6) = 50.76 and (2x-71.6) = - 50.76
that's how u'll get the other angle
u write the " 2/5 pi + sin (theta) " on your calculator , replacing theta with the value 2.1 and press = , write the answer correct to 3 decimal places , then replace the 2.1 value on your calculator , using the " ans" button , and get theta 3 , keep pressing = and writing down the values till they give u the same value correct to 2 decimal places , in this question it will be 2.11
Integrating this gives you ---> ln (1+x^2)/2
Yes exactly this. So the equation is -3 ln (1) +2 ln (4+1) + 3 ln(2-0) - 0 = ln25 + ln8 . What am I doing wrong?
i was just thinking of messaging you! could you please solve that integration question now? November 2011 paper 33 Q10
for the integral of 1/(a square+x square) the integral Wud b 1/a tan inverse of (x/a) +c
Still very difficult to show the solution here !
is there any way at all that you could help me?
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