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Mathematics: Post your doubts here!

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assalamoalaikum wr wb!

alright...now u know the other angle would be 360 - 50.76 ...right? but that is out of the range given..now remember that in the fourth quadrant angle can either be 360 - x or alternatively be written as "-x "
so we have
(2x-71.6) = 50.76 and (2x-71.6) = - 50.76

that's how u'll get the other angle ;)
ooh now that makes more sense!
 
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Okay one more doubt, O/N/11 p32 q6 pt. (ii)

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_qp_32.pdf

:) thanks

Edit: Changed p31 to p32 , apologies!

sqr(10).cos [2 θ - 71.6'] = 2 ; 0' < θ < 90'
>> 2 θ - 71.6' = cos–1 [2 /sqr(10)].....
......................= 50.8'
>> θ = (50.8' + 71.6'] / 2 = 61.2'
also,
2 θ - 71.6' ~ 360' - 50.8' [since, cosθ = cos(360-θ) = cos(-θ)]
>> 2θ = 380.8' ~ 20.8' [since, 380.8' = 360' (1 complete rotation) + 20.8']
>> θ = 10.4'

θ = 61.2', 10.4'
 
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http://www.xtremepapers.com/papers/...S Level/Mathematics (9709)/9709_s11_qp_31.pdf
http://www.xtremepapers.com/papers/...S Level/Mathematics (9709)/9709_s11_ms_31.pdf

can someone do no.6 mmm confused


question no.8 how to show the arguement u is PIE/2 i knw its pie by 2 since i got u=-3i but how to show should i draw a graph or i should just say that the cordinates (0,-3i) lies on the y axis thus the angle made with the x axis is -pie/2
Anyone :?


and question no.10

well the above questions are my prev post which no1 has answerd :D
question 6 :
first: the area of the minor sector AOB =0.5 X 10^2 theta = 50 theta
the area of the major sector AOB = 0.5 X 10 ^2 X( 2 pi - theta) = 100 pi - 50 theta
the area of triangle AOB = 0.5 X 10^2 sin(theta) = 50 sin (theta)
area of the small segmant AB = area of minor sector AOB - area of triangle AOB
area of the large segmant AB = area of the major sector AOB + area of triangle AOB
now put them all together
50 theta - 50 sin( theta) = 0.25 X ( 11 pi - 50 theta + 50 sin (theta) )
50 theta - 50 sin(theta) = 25 pi - 12.5 theta +12.5 sin( theta)
62.5 theta = 25 pi + 62.5 sin (theta) ( divide by 62.5)
theta = 2/5 pi + sin (theta)
and continue normally

question 10 is answered here http://www.xtremepapers.com/community/threads/mathematics-post-your-doubts-here.9599/page-69
post 1366
 
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can anyone please explain about how to find arguments of a complex number :/ Please explain the method it would mean alot ! thanks !
 
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question 6 :
first: the area of the minor sector AOB =0.5 X 10^2 theta = 50 theta
the area of the major sector AOB = 0.5 X 10 ^2 X( 2 pi - theta) = 100 pi - 50 theta
the area of triangle AOB = 0.5 X 10^2 sin(theta) = 50 sin (theta)
area of the small segmant AB = area of minor sector AOB - area of triangle AOB
area of the large segmant AB = area of the major sector AOB + area of triangle AOB
now put them all together
50 theta - 50 sin( theta) = 0.25 X ( 11 pi - 50 theta + 50 sin (theta) )
50 theta - 50 sin(theta) = 25 pi - 12.5 theta +12.5 sin( theta)
62.5 theta = 25 pi + 62.5 sin (theta) ( divide by 62.5)
theta = 2/5 pi + sin (theta)
and continue normally

question 10 is answered here http://www.xtremepapers.com/community/threads/mathematics-post-your-doubts-here.9599/page-69
post 1366

how to do part ii of question 6
 
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assalamoalaikum wr wb!

alright...now u know the other angle would be 360 - 50.76 ...right? but that is out of the range given..now remember that in the fourth quadrant angle can either be 360 - x or alternatively be written as "-x "
so we have
(2x-71.6) = 50.76 and (2x-71.6) = - 50.76

that's how u'll get the other angle ;)
what should we do if Rsin(x-theeta) is the condition.How will we find the second answer in the range?
 
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how to do part ii of question 6
u write the " 2/5 pi + sin (theta) " on your calculator , replacing theta with the value 2.1 and press = , write the answer correct to 3 decimal places , then replace the 2.1 value on your calculator , using the " ans" button , and get theta 3 , keep pressing = and writing down the values till they give u the same value correct to 2 decimal places , in this question it will be 2.11
now find AB using the cosin rule
AB^2 = OB^2 + OA ^2 - ( 2X OA X OB X cos (2.11) )
you'll get AB = 17.4
 
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