http://www.xtremepapers.com/papers/...S Level/Mathematics (9709)/9709_w11_qp_32.pdf
Q. 8 (ii) from the paper. For some reason I'm getting ln25 + ln8. Please help!
Q. 8 (ii) from the paper. For some reason I'm getting ln25 + ln8. Please help!
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if u mean for part ii , then u just assume any value, I assumed it was 2How to get the initial value for q4 ?
http://www.xtremepapers.com/CIE/International A And AS Level/9709 - Mathematics/9709_s11_qp_32.pdf
Please help me !
question 6 :
first: the area of the minor sector AOB =0.5 X 10^2 theta = 50 theta
the area of the major sector AOB = 0.5 X 10 ^2 X( 2 pi - theta) = 100 pi - 50 theta
the area of triangle AOB = 0.5 X 10^2 sin(theta) = 50 sin (theta)
area of the small segmant AB = area of minor sector AOB - area of triangle AOB
area of the large segmant AB = area of the major sector AOB + area of triangle AOB
now put them all together
50 theta - 50 sin( theta) = 0.25 X ( 11 pi - 50 theta + 50 sin (theta) )
50 theta - 50 sin(theta) = 25 pi - 12.5 theta +12.5 sin( theta)
62.5 theta = 25 pi + 62.5 sin (theta) ( divide by 62.5)
theta = 2/5 pi + sin (theta)
and continue normally
question 10 is answered here http://www.xtremepapers.com/community/threads/mathematics-post-your-doubts-here.9599/page-69
post 1366
what should we do if Rsin(x-theeta) is the condition.How will we find the second answer in the range?assalamoalaikum wr wb!
alright...now u know the other angle would be 360 - 50.76 ...right? but that is out of the range given..now remember that in the fourth quadrant angle can either be 360 - x or alternatively be written as "-x "
so we have
(2x-71.6) = 50.76 and (2x-71.6) = - 50.76
that's how u'll get the other angle
How to get the initial value for q4 ?
http://www.xtremepapers.com/CIE/International A And AS Level/9709 - Mathematics/9709_s11_qp_32.pdf
Please help me !
u write the " 2/5 pi + sin (theta) " on your calculator , replacing theta with the value 2.1 and press = , write the answer correct to 3 decimal places , then replace the 2.1 value on your calculator , using the " ans" button , and get theta 3 , keep pressing = and writing down the values till they give u the same value correct to 2 decimal places , in this question it will be 2.11how to do part ii of question 6
Integrating this gives you ---> ln (1+x^2)/2How Wud u integrate 1/(1+X^2) ?
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_qp_32.pdf
Q. 8 (ii) from the paper. For some reason I'm getting ln25 + ln8. Please help!
No it doesnt differential of x square is 2x not 2. There's a formula for it.
Yes exactly this. So the equation is -3 ln (1) +2 ln (4+1) + 3 ln(2-0) - 0 = ln25 + ln8 . What am I doing wrong?you must have this integrated equation
(-3 ln (2-x) + 2 ln (4+x^2))
got this?
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_qp_31.pdf
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_ms_31.pdf
question 7 part ii)
can any one give a rough idea of the sketch????
i was just thinking of messaging you! could you please solve that integration question now? November 2011 paper 33 Q10
Still very difficult to show the solution here !i was just thinking of messaging you! could you please solve that integration question now? November 2011 paper 33 Q10
is there any way at all that you could help me?Still very difficult to show the solution here !
I have done the question, it is tricky but very easy.
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