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wow, its been ten days and no ones answered my question
i just found out the answer myself
thankyou xtremepapers....for nothing
i just found out the answer myself
thankyou xtremepapers....for nothing
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IgoforA said:please help
dy/dx= e^-3x { sec^2x -3tanx } i hope m not wrong...then..u cannot get any values from e^-3x.....now...take secx and tanx in sinx and cosx..u will get it..!! otherwise..i will give u the solution after an hour..!! m goin out right now..!kamina1 said:i hve found the derivative but it is not further simplifying...
NehaKush said:The parametric equations of a curve are
x = a cos3 t, y = a sin3 t,
(i) Express
dy
dx
in terms of t. [3]
(ii) Show that the equation of the tangent to the curve at the point with parameter t is
x sin t + y cos t = a sin t cos t. [3]
(iii) Hence show that, if this tangent meets the x-axis at X and the y-axis at Y, then the length of XY
is always equal to a. [2]
thanx.. its june2009, Question6
for 8IgoforA said:june 2011 paper 31 please help??
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