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what do u mean x2?
ohh ok
dude i did it my way first taking P(X>9.2) then adding the probability found to P(X<7.2) ul get the same answer
I believe that in june 2011 they took the range from 1 to 10 not from 0 -9
ok dude listen this might calm you whenever N(number of trials) is very large like above 20 or so always do np and nq to check whether it converges to normal. mostly 5 marks qs like this are to be converted to normal. but always do check. if np >5 or nq >5 then uve got a normalplease in june 11 63 S1 question 5)iii), i need to know why they used CONTINUITY CORRECTION in the mark scheme although there was no term in the question indicating this like normal approximation or suitable approximation??
please answer soon to help me and others
dude i did it my way first taking P(X>9.2) then adding the probability found to P(X<7.2) ul get the same answer
in the summer 2003 one the class boundaries are defined and are continuous like from 0-5 then 5-10 but in june 2011 they arent defined and arent continuous either. so in the 2011 one you have to subtract .5 from the upper class boundaries and add .5 to the lower class boundary
no problem bro just pray for meThanks got it
BTW could you explain http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w09_qp_62.pdf Q1 - (ii)? i couldnt find it in the previous pages and i really dont have time to keep scrolling through them all so please?
anyways you know that q3 is 75 percent of the data right? is the area less then q3 will be.75. P(X<63)=.75 solve and enjoy
P(X>20)=.10 standardize and solve but dont forget to underroot variance since you have to deal with s.d
no problem bro just pray for me
and yes i sure will
but that doesn't five the 4.5 or other values in the markscheme
thank you so much.if dont understand, just let me know.
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