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Mathematics: Post your doubts here!

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please in june 11 63 S1 question 5)iii), i need to know why they used CONTINUITY CORRECTION in the mark scheme although there was no term in the question indicating this like normal approximation or suitable approximation??
please answer soon to help me and others :)
ok dude listen this might calm you whenever N(number of trials) is very large like above 20 or so always do np and nq to check whether it converges to normal. mostly 5 marks qs like this are to be converted to normal. but always do check. if np >5 or nq >5 then uve got a normal
 
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I believe that in june 2011 they took the range from 1 to 10 not from 0 -9
in the summer 2003 one the class boundaries are defined and are continuous like from 0-5 then 5-10 but in june 2011 they arent defined and arent continuous either. so in the 2011 one you have to subtract .5 from the upper class boundaries and add .5 to the lower class boundary
 
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in such qs always write down the number of times an alphabet is being repeated...p=2 s=2 h=1 i=1 n=1 e=1 a=1
select 4 letters which contain NO P and either 1s or 2s. First vl solve for 1s
-since you know that you have to take that s for sure u wont select it hence its 5c3 this means u have selected 3 letters from h i n e a.
-same goes for 2s but this time u have to select 2 letters from h i n e a= so its 5C2 hence sum them up to get 20.
 
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plz jus explain the ans for the (iv) part. i understood the rest.Screenshot_2012-05-23-06-55-02-1.png
here's the mark scheme:
Screenshot_2012-05-23-19-11-22.png
 
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