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Srry but havent done vectors yet.
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Srry but havent done vectors yet.
Oh okay Jazaka Allah khairan...I got it
Just use the cosine rule for part a:
For second part use help from following site. I would hv done it bt im abit busy
u need help in this question or what..?Oct/Nov 2009 Q8
The first term of an arithmetic progression is 8 and the common difference is d, where d is not equals to 0. The first term, the fifth tern and the eight term of this arithmetic progression are the first term, the second term and the third term, respectively, of a geometric progression whose common ratio is r.
(i) write down two equations connecting d and r. Hence show that r = 3/4 and find the value of d. [6]
Here are the answers broOct/Nov 2009 Q8
The first term of an arithmetic progression is 8 and the common difference is d, where d is not equals to 0. The first term, the fifth tern and the eight term of this arithmetic progression are the first term, the second term and the third term, respectively, of a geometric progression whose common ratio is r.
(i) write down two equations connecting d and r. Hence show that r = 3/4 and find the value of d. [6]
No more informations are given?a stone is dropped from the top of a building of a hight 20m. Find the time it takes to reach the ground and the velocity with which it hit's the ground.
can Any1 , help in this question?
Why else would I post an entire question here then?u need help in this question or what..?
Thank you so much!Here are the answers bro
Hope it helps.
(And srry for the handwriting! )
No prob!Thank you so much!
a stone is dropped from the top of a building of a hight 20m. Find the time it takes to reach the ground and the velocity with which it hit's the ground.
can Any1 , help in this question?
a stone is dropped from the top of a building of a hight 20m. Find the time it takes to reach the ground and the velocity with which it hit's the ground.
can Any1 , help in this question?
2as=v^2-u^2No more informatVions are given?
for 5 (i)... differentiate the given equation and dy/dx= -1(x-3)^-2 + 1 and d^2y/dx^2 = 2(x-3)^-3Hey guys,
I really need help with question 5 of the following paper:
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w10_qp_13.pdf
I've looked at the answers and still couldn't figure it out :/ Both parts please, any help would be greatly appreciated.
Thanks in advance.
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