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I hope its clear!!!
take care!bye
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I hope its clear!!!
can u help mehttp://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_qp_32.pdf
Please help... question number 6(ii)
i have the same question did u find an answer ?http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_qp_32.pdf
Please help... question number 6(ii)
I need help in the following differentiation question:
Find the equation of the tangent to the curve y = x^2, which is parallel to the line y = x.
Please reply with a detailed solution..
can anyone solve this SinA=2sinB and CosA+2CosB=2
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s05_qp_3.pdf
I need help for no. 5(i)
Ohh that's tough
There you go, the full solutions:
Hope this helps. Peace.
thanks a ton sirsinA =2sinB -------(1)
cosA +2 cosB =2 =======> cosA =2(1-cosB) -----------(2)
Squaring (1), we have sin^2 A = 4 sin^2 B ----------(3)
Squaring (2), we have cos^2 A= 4(1-cosB)^2 ---------(4)
(3)+(4): 1= 4 sin^2 B + 4 (1-cosB)^2
1= 4 sin^2 B + 4 - 8cos B + 4cos^2 B
1 = 4 ( sin^2 B + cos^2 B) +4 -8cosB
1= 4 +4 -8cosB
8 cosB =7 =====> B = arc cos (7/8) =28.96 deg (shown) and A=75.52 deg (shown)
Hope this helps. Peace.
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