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Mathematics: Post your doubts here!

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sorry that was lame.

here

( 4 - (2^x))= -10
2^x = 14
x= ln 14 divided by ln 2
 
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http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s09_qp_1.pdf
No. 10 (ii)

This question seems easy.. how do you find the value of A? Please help
An explanation will be appreciated..

Salvatore, for the first part you have completed the square and got answer in this form : 2 ( x -3 ) ^ 2 - 5

So this mean that we have a minimum point when x = 3. The line x=3 acts as a line of symmetry for the quadratic curve. That is a turning point at the point x=3, now since x is greater or equal to zero, this would mean that A should be 6.

If i could have provided you with a sketch or a video, you would have better understood. Hope it help though.
 
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Salvatore, for the first part you have completed the square and got answer in this form : 2 ( x -3 ) ^ 2 - 5

So this mean that we have a minimum point when x = 3. The line x=3 acts as a line of symmetry for the quadratic curve. That is a turning point at the point x=3, now since x is greater or equal to zero, this would mean that A should be 6.

If i could have provided you with a sketch or a video, you would have better understood. Hope it help though.
Thank you for your reply..

I understand that the line x=3 acts as a line of symmetry since it is the turning point.. but I don't get why A is 6 (If x >= 0). Could you please explain that?

Along with the above, I also need help in qn 10 (v) and 11 (iii).. please please help me solve the questions with some explanation.
I'll really appreciate if you could do that for me.

Thanks a lot
Waiting for your reply..
 
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Thank you for your reply..

I understand that the line x=3 acts as a line of symmetry since it is the turning point.. but I don't get why A is 6 (If x >= 0). Could you please explain that?

Along with the above, I also need help in qn 10 (v) and 11 (iii).. please please help me solve the questions with some explanation.
I'll really appreciate if you could do that for me.

Thanks a lot
Waiting for your reply..


Try to list down the values in a table

x 0 1 2 3 4 5 6 7 8

y 13 3 -3 -5 -3 3 13
[Line of Symmetry]

Can you visualise it...?

10 (iv) it has an inverse because it is 1-1

10 (v) Let g(x) = y
we should take the completed form so that x is able to be made subject of formula

2 ( x - 3 ) ^ 2 - 5 = y

2 ( x - 3 ) ^ 2 = y + 5

( x - 3 ) ^ 2 = ( (y+5) / 2 )

( x - 3 ) = PlusMinus Square Root of ( (y+5) / 2 )

x = 3 PlusMinus Square Root of ( (y+5) / 2 )

Now we have to choose either the plus sign or the minus sign. Since the domain is greater than 4 we choose the "plus" sign.

Hence g inverse of x = 3 + ( ( x + 5 ) /2 ) ^ (1/2)
 
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Ok so taking A B C D as an example, what will be the combination taking three ata time?


Combination would be 4 C 3 = 4

Listing : A B C or A C D or A B D or B C D

While if we had to permute, or question was in how many ways can three letters of the word " BACD" can be arranged, the answer would be 4 P 3 ( permutating 3 from 4 ) = 24

Listing

A B C or A C D or A B D or B C D and all these ; each have 3! ways of writing them i.e 4 * 3 ! = 24
 
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Try to list down the values in a table

x 0 1 2 3 4 5 6 7 8

y 13 3 -3 -5 -3 3 13
[Line of Symmetry]

Can you visualise it...?

10 (iv) it has an inverse because it is 1-1

10 (v) Let g(x) = y
we should take the completed form so that x is able to be made subject of formula

2 ( x - 3 ) ^ 2 - 5 = y

2 ( x - 3 ) ^ 2 = y + 5

( x - 3 ) ^ 2 = ( (y+5) / 2 )

( x - 3 ) = PlusMinus Square Root of ( (y+5) / 2 )

x = 3 PlusMinus Square Root of ( (y+5) / 2 )

Now we have to choose either the plus sign or the minus sign. Since the domain is greater than 4 we choose the "plus" sign.

Hence g inverse of x = 3 + ( ( x + 5 ) /2 ) ^ (1/2)

Thanks a lot bro.. ur awesome!
I think you forgot about no 11 (iii).. please explain if possible.
Sorry for bothering :)
 
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Cn anyone help me out ???? Write the following complex number in modulus argument form .
Question = 1+2i (also whr cn i find notes in complex number????)

For the question; the real part is 1 while the imaginary part is 2.

The modulus; R = square root of [(1) ^2 + (2) ^ 2 ] = square root 5 = 5 ^ (1/2)
Its argument = tan inverse of ( 1/2 ) = & [ evaluate it, i am going to call it "&"]

In Trigonometric Form = R ( cos & + i sin & )
In Exponential Form = R e ^ ( i & )
 
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Thanks a lot bro.. ur awesome!
I think you forgot about no 11 (iii).. please explain if possible.
Sorry for bothering :)

LOL, thanks for saying that i am awesome. hahaha but i want to become LEGEND...wait for it....LEGENDAAAAARYYYYYYYYYY. [ Dialogue of Barney Stinson ]

Well to answer 11 (iii), i presume that you have successfully tackled part (i) and part (ii), i.e. you already know the coordinates of A, B and the equation of the normal to the curve at C.

Now, the first step is to find coordinate of C, by solving simultaneously the equation of curve and the equation of the curve at C. Just find its x coordinate. Infact you will get two values of x, reject the value of x which is smaller than the x coordinate of point A.

Let us say that Area H = integration of the equation of normal to the curve with lower limit the x ordinate of coordinate C and upper limit the x ordinate of coordinate B

Let us say that Area K = integration of the equation of the curve with lower limit the x ordinate of coordinate C and upper limit the x ordinate of coordinate B

Try to visualise what the above area represents and you would come to the conclusion that

the area of the shaded region = Area H - Area K

Hope that it helps, if it does then make du'a for me and for all the oppressed muslims wherever they are especially the Syrian people and Afghan people.
 
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