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guys can you solve this question ?
integration of (xe^2x) dx
We will have to solve by part. Consider Late, x is algebraic while e ^ ( 2*x) is exponential.
Hence; u = x ; v = ( e ^ ( 2* x ) ) / 2
du/dx = 1 ; dv/dx = e ^ ( 2*x)
integration of (xe^2x) dx = u * v - integration of v du
= x * ( e ^ ( 2* x ) ) / 2 - integration of 1 * ( e ^ ( 2* x ) ) / 2
= x * ( e ^ ( 2* x ) ) / 2 - ( e ^ ( 2* x ) ) / 4