Mathematics: Post your doubts here!

[daredevil]

HELLPP Q.1 and Q.2 of M/J 12 .. Paper 62
please solve that for me... thanx

 

[syed1995]

where can i get examiner reports

Read the question again. Limits are -Pi/2 to Pi/2. so you will ignore any values greater than Pi/2.


The examiner reports are all available on xtremepapers... here:

 

[daredevil]

can some1 pleassee tell me how to make a box and whiskers diagram??

 

[Dug]

can some1 pleassee tell me how to make a box and whiskers diagram??

Here

 

[Rutzaba]

Hi guys.... Please help me with these questions... would be appreciated... Thanks
Q5,Q6ii, Q7iii, Q8i, Q9ii

Q 6 part two a and b.
a)A conjugate in simple words mean that the sign ( that is negative or positive) of the imaginary number (the coefficient of i ) would change.
z= √3 + i
z*= √3 - i
1....things to remember = i = √-1 and thus i^2= -1
2.... if there is a term in i in the denominator and we have to remove it... we multiply the whole term with its conjugate and divide the whole term with its conjugate too.
we need to find
a) 2z +z* = 2(√3 +i) + √3- i
2 √3 +2i + √3 -i
3 √3 + i ...... ans.

b)because the format of the fraction isnt good here i have made u a pic to understand from

http://i1275.photobucket.com/albums/y444/Rutzaba/xpc_zpsd8fbcce5.png

 

[daredevil]

Here

can play the video becuz youtube is not working in pakistan... do u have anything else??

 

[Dug]

can play the video becuz youtube is not working in pakistan... do u have anything else??

Here

 

[parthrocks]

can someone plz help me with this..I need the solution asap!plz
Maths expert
Need it asap.plz attach a scan if possible showing all the steps.ok

 

[parthrocks]

and this one too plz help

 

[daredevil]

Here

thannkuu

 

[daredevil]

can someone plz help me with this..I need the solution asap!plz
Maths expert
Need it asap.plz attach a scan if possible showing all the steps.ok

c u can do it like this :
separate the 4 and the 10s :-

4^4 x (10^-1 x 10^-2 x 10^-3 x 10^1)
= 256 x 10^-1-2-3+1
= 256 x 10^-5
= 0.00256
=0.002560

don't be confused because of the last zero because it is a trick. it does not actually matter how many zeros we put at the end the answer is still 0.002560

get it??

 

[zunair]

Thanks a lot

 

[yubakkk]

 

[yubakkk]

plz answer will working.

 

[Fatima18]

http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_w04_qp_1.pdf
Hi guys!
How to do number 9 ii )???
Also, I solved 9 iv and Im getting square root of x + 9 then + 3, hoever the answer key has a square root under everything including +3..why is that??
Pls asap..Thank you!

 

[Dug]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w04_qp_1.pdf
Hi guys!
How to do number 9 ii )???
Also, I solved 9 iv and Im getting square root of x + 9 then + 3, hoever the answer key has a square root under everything including +3..why is that??
Pls asap..Thank you!

ii)
f(x) = g(x)
2x - a = x^2 - 6x
x^2 - 8x + a = 0

Since one real solution, D = 0
D = b^2 - 4ac = 0
(-8)^2 - 4(1)(a) = 0
64 - 4a = 0
a = 16

iv)
let y = x^2 - 6x
y = x^2 - 6x + (-3)^2 - (-3)^2
y = (x - 3)^2 - 9
(x - 3)^2 = y + 9
x - 3 = √(y + 9)
x = √(y + 9) + 3

h-1(x) = √(x + 9) + 3

Domain: x ≥ -9

 

[PhyZac]

I'm guessing this is for the P3 paper.

9i) y = e^(-x/2) √(1+2x)
dy/dx = -1/2 e^(-x/2) * √(1+2x) + 1/2* 2 * (1+2x)^(-1/2) * e^(-x/2)
dy/dx = [-e^(-x/2) * √(1+2x)]/2 + e^(-x/2)/ √(1+2x)

For M, dy/dx = 0
[-e^(-x/2) * √(1+2x)]/2 + e^(-x/2)/ √(1+2x) = 0
Take LCM
[-e^(-x/2) * √(1+2x)* √(1+2x) + e^(-x/2) *2] / 2√(1+2x) =0
cross multiply, so the denominator becomes 0
-e^(-x/2) * (1+2x) +2e^(-x/2) = 0
take -e^(-x/2) common-
-e^(-x/2) [(1+2x) -2] =0
so,
-e^(-x/2) = 0 (NA) or -(1+2x) -1 = 0
1+2x -2 = 0
2x= 1
x =1/2

Jazaki Allah khairan...Thanks alottt...!! Yes sorry it was for paper 3 ....THAnk u so much...May Allah reward you with the best of the two worlds. In Sha Allah your will get A*'s Ameen...THANK YOU for you help...May Allah have mercy on you and your family Ameen

 

[talalz94]

hey i need help in these P3 questions ...
Question 7, winter 2012 / 33 . please explain as much as u can especially the limits .. how to find them out ?

 

[mominzahid]

did u understand the question that i solved for u?
im gud at maths on a paper but it takes ten thousand years for me to type this stuff.i will solve other qsas soon as possible

Urrmm yes i think i didd... my concepts needed some refreshment so watched a tutorial then saw ur solution.. I got it.
THank you

 

[Muhammad Bin Anis]

Can any one of you explain Q8 part (ii) and Q9 part (ii)??
(this is from nov 2012 / p32)